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ioda
2 years ago
6

what type of reaction mechanism is operative in the conversion of 2-methyl-2-butanol into 2-chloro-2-methylbutane?

Chemistry
1 answer:
UNO [17]2 years ago
8 0

Answer:

Below

Explanation:

The reaction is a Substitution SN1 mechanism

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A gas has a density of 1.57 g/L at 40.0 °C and 2.00 atm of pressure. What is the identity of the gas?
Naddika [18.5K]

Answer:

Neon

Explanation:

Step 1: Given and required data

  • Density of the gas (ρ): 1.57 g/L
  • Temperature (T): 40.0°C
  • Pressure (P): 2.00 atm
  • Ideal gas constant (R): 0.08206 atm.L/mol.K

Step 2: Convert T to Kelvin

We will use the following expression.

K = °C + 273.15 = 40.0 + 273.15 = 313.2 K

Step 3: Calculate the molar mass of the gas (M)

For an ideal gas, we will use the following expression.

ρ = P × M/R × T

M = ρ × R × T/P

M = 1.57 g/L × 0.08206 atm.L/mol.K × 313.2 K/2.00 atm

M = 20.17 g/mol

The gas with a molar mass of 20.17 g/mol is Neon.

6 0
2 years ago
How many moles of carbonate are there in sodium carbonate​
vaieri [72.5K]

There are 0.566 moles of carbonate in sodium carbonate.

<h3>CALCULATE MOLES:</h3>
  • The number of moles of carbonate (CO3) in sodium carbonate (Na2CO3) can be calculated by dividing the mass of carbonate in the compound by the molar mass of the compound.

  • no. of moles of CO3 = mass of CO3 ÷ molar mass of Na2CO3

  • Molar mass of Na2CO3 = 23(2) + 12 + 16(3)

  • = 46 + 12 + 48 = 106g/mol

  • mass of CO3 = 12 + 48 = 60g

  • no. of moles of CO3 = 60/106

  • no. of moles of CO3 = 0.566mol

  • Therefore, there are 0.566 moles of carbonate in sodium carbonate.

Learn more about number of moles at: brainly.com/question/1542846

5 0
2 years ago
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-Are the most used in daily life and basic human needs

(such as oxygen,nitrogen,carbon, etc)

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3 years ago
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Swer questions 12 B D 12 Classify each model A-D as either an ele- ment, a compound, or a mixture. Explain your reasoning for ea
MrRissso [65]

Answer:

13-b

Explanation:

because 13-b is close to a and 12

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2 years ago
PLEASE HELP NO LINKS OR FILES
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Answer:

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