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agasfer [191]
2 years ago
9

A ball is thrown straight up from the ground level, with an initial velocity of 34.3 m/s.34.3 m/s. How high is the ball thrown

Physics
1 answer:
brilliants [131]2 years ago
6 0

The maximum height attained by the ball is 60 m.

<h3>What is the maximum height?</h3>

We know that the maximum height can be obtained from the equation;

v^2 = u^2 - 2gh

v =  final velocity

u = initial velocity

g = acceleration due to gravity

h = maximum height

Since the final velocity is 0 m/s at maximum height then;

u^2 = 2gh

h = u^2/2g

h = (34.3)^2/2 * 9.8

h = 60 m

Learn kore about maximum height:brainly.com/question/6261898

#SPJ1

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0002 - 2nd Step

0003 - 3rd Step

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Looking at this pattern, it is obvious this digits are in base 5 because once we count to 4 in a unit, we move to the next at 1.

Thus,at Mady's 2010th step, we'll convert to base 5,thus 2010 in base 5 is calculated as;

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2 years ago
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Hope this helped.
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