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2 years ago

A ball is thrown straight up from the ground level, with an initial velocity of 34.3 m/s.34.3 m/s. How high is the ball thrown

Physics

1 answer:

brilliants [131]2 years ago

6 0

The maximum height attained by the ball is 60 m.

<h3>What is the maximum height?</h3>

We know that the maximum height can be obtained from the equation;

v^2 = u^2 - 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = maximum height

Since the final velocity is 0 m/s at maximum height then;

u^2 = 2gh

h = u^2/2g

h = (34.3)^2/2 * 9.8

h = 60 m

Learn kore about maximum height:brainly.com/question/6261898

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<h2>Answer:</h2>

The current will drop to half of its original value.

<h2>Explanation:</h2>

To solve this problem, we must use Ohm's law that states that in a circuit the voltage $v$ across a resistor is directly proportional to the current that flows through that circuit. In other words:

$v \propto Ri \\ \\ or: \\ \\ v=Ri \\ \\ It's \ also \ valid: i=\frac{v}{R}$

According to our problem, if the voltage in the circuit is held constant while the resistance double, that is $R_{New}=2R \ and \ v_{New}=v$ . So:

$v=R_{New}i_{New} \\ \\ v=2Ri_{New} \\ \\ Isolating \ i_{New}: \\ \\ i_{New}=\frac{v}{2R} \therefore i_{New}=\frac{1}{2}\frac{v}{R} \therefore i_{New}=\frac{1}{2}i$

In conclusion, <em>the current will drop to half of its original value.</em>

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3 years ago

Two wires have the same resistance and radius. If the wires are made of copper and platinum with resistivities respectively of 1

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Answer:

L1/L2 = 6.47

Explanation:

In order to calculate the ratio of the lengths of the wires you use the following formula for the resistivity of a wire:

$\rho=\frac{\pi r R}{L}$ (1)

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R: resistance of the wire

L: length of the wire

Then, you have for each wire:

$\rho_1=\frac{\pi r_1^2R_1}{L_1}=1.70*10^{-8}\Omega.m\\\\\rho_2=\frac{\pi r_2^2R_2}{L_2}=11.0*10^{10^{-8}}\Omega.m$

The resistance and radius of the wires are the same, that is, R1 = R2 = R and r1 = r2 = r. By taking into account this last and dive the equation for the wire 2 into the wire 1, you obtain:

$\frac{\rho_2}{\rho_1}=\frac{11.0*10^{-8}\Omega.m}{1.70*10^{-8}\Omega.m}=\frac{L_1}{L_2}\\\\\frac{L_1}{L_2}=6.47$

The ratio of the lengthd of the wires is L1/L2 = 6.47

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3 years ago

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3 years ago

A 50-kg man is driving his snowmobile at a constant speed. The engine applies a force of 360 N and the coefficient of kinetic fr

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Answer:

134 kg

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On level ground, the normal force equals the combined weight:

(m + 50)g μ = 360

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m ≈ 134 kg

Round as needed.

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