Question

A ball is thrown straight up from the ground level, with an initial velocity of 34.3 m/s.34.3 m/s. How high is the ball thrown

Answer 1

The maximum height attained by the ball is 60 m.

What is the maximum height?

We know that the maximum height can be obtained from the equation;

v^2 = u^2 - 2gh

v =  final velocity

u = initial velocity

g = acceleration due to gravity

h = maximum height

Since the final velocity is 0 m/s at maximum height then;

u^2 = 2gh

h = u^2/2g

h = (34.3)^2/2 * 9.8

h = 60 m

Learn kore about maximum height:brainly.com/question/6261898

#SPJ1