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AlladinOne [14]
3 years ago
8

A 50-kg man is driving his snowmobile at a constant speed. The engine applies a force of 360 N and the coefficient of kinetic fr

iction between the snowmobile and the snow is 0.2. What is the mass of the snowmobile?
Physics
1 answer:
S_A_V [24]3 years ago
8 0

Answer:

134 kg

Explanation:

The snowmobile is moving at constant speed, so the acceleration is 0.

Sum of the forces in the x direction:

∑F = ma

F − 360 = 0

F = 360

Friction force equals the normal force times the coefficient of friction:

Nμ = 360

On level ground, the normal force equals the combined weight:

(m + 50)g μ = 360

m + 50 = 360 / (gμ)

m = -50 + 360 / (gμ)

m = -50 + 360 / (9.8 × 0.2)

m ≈ 134 kg

Round as needed.

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Two charged particles are located on the x axis. The first is a charge 1Q at x 5 2a. The second is an unknown charge located at
sergejj [24]

Answer:

Q_2 = +/- 295.75*Q

Explanation:

Given:

- The charge of the first particle Q_1 = +Q

- The second charge = Q_2

- The position of first charge x_1 = 2a

- The position of the second charge x_2 = 13a

- The net Electric Field produced at origin is E_net = 2kQ / a^2

Find:

Explain how many values are possible for the unknown charge and find the possible values.

Solution:

- The Electric Field due to a charge is given by:

                               E = k*Q / r^2

Where, k: Coulomb's Constant

            Q: The charge of particle

            r: The distance from source

- The Electric Field due to charge 1:

                               E_1 = k*Q_1 / r^2

                               E_1 = k*Q / (2*a)^2

                               E_1 = k*Q / 4*a^2

- The Electric Field due to charge 2:

                               E_2 = k*Q_2 / r^2

                               E_2 = k*Q_2 / (13*a)^2

                               E_2 = +/- k*Q_2 / 169*a^2

- The two possible values of charge Q_2 can either be + or -. The Net Electric Field can be given as:

                               E_net = E_1 + E_2

                               2kQ / a^2 = k*Q_1 / 4*a^2 +/- k*Q_2 / 169*a^2

- The two equations are as follows:

        1:                   2kQ / a^2 = k*Q / 4*a^2 + k*Q_2 / 169*a^2

                               2Q = Q / 4 + Q_2 / 169

                               Q_2 = 295.75*Q

        2:                    2kQ / a^2 = k*Q / 4*a^2 - k*Q_2 / 169*a^2

                               2Q = Q / 4 - Q_2 / 169

                               Q_2 = -295.75*Q

- The two possible values corresponds to positive and negative charge Q_2.

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An increase in the magnitude of velocity is??
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It means the speed of the object is increasing
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Describe what a high and low frequency electromagnetic wave look like:
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A high electromagnetic wave has short, very fast, frequent waves.

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A 2.0-kg block is on a perfectly smooth ramp that makes an angle of 30° with the horizontal. (a) What is the block’s acceleratio
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