All categories

3 years ago

A cell of internal resistance 2 ohms supplies current to a 6 ohms resistor. What is the efficiency of the cell?.

Physics

1 answer:

Margaret [11]3 years ago

4 0

75% is the efficiency of the cell.

Explanation:

Internal resistance is the resistance generated due to the devices present in the circuit. Most preferably, it is the resistance of the battery connected to the circuit.

As the current, resistance of the resistor and the internal resistance of the battery is given as 6 A, 6 ohms and 2 ohms.

Then the efficiency of the cell is $E = \frac{IR}{I (R+r)} =\frac{R}{r+R}$

So, the efficiency of the cell is $E=\frac{R}{r+R}$

Then, E = $\frac{6}{2+6}=\frac{6}{8}$

So, the efficiency is 75%.

75% is the efficiency of the cell.

You might be interested in

2. A 55 kg woman has a momentum of 200 kg m/s. What is her velocity?

NeTakaya

Answer:

$\boxed {\tt 3.63636364 \ m/s}$

Explanation:

Velocity can be found using the following formula:

$v=\frac{p}{m}$

where p is the momentum and m is the mass.

The woman has a mass of 55 kilograms and a momentum of 200 kilogram meters per second.

$p= 200 \ kgm/s\\m=55 \ kg$

Substitute the values into the formula.

$v=\frac{200 \ kg m/s}{55 \ kg}$

Divide. Note that the kilograms, or kg, will cancel each other out.

$v=\frac{200 \ m/s}{55}$

$v= 3.63636364 \ m/s$

The woman's velocity is 3.63636364 meters per second.

6 0

3 years ago

Identify the temperature that is equivalent to 95°F. Use this formula to convert the temperature

Stells [14]

The answer is 35 degrees Celsius. Hope I helped :) Please vote brainliest.

7 0

3 years ago

Read 2 more answers

What is a hydraulic system

Simora [160]

Explanation:

Hydraulic systems use the pump to push hydraulic fluid through the system to create fluid power. The fluid passes through the valves and flows to the cylinder where the hydraulic energy converts back into mechanical energy. The valves help to direct the flow of the liquid and relieve pressure when needed

7 0

3 years ago

A piano wire with mass 2.95 g and length 79.0 cm is stretched with a tension of 29.0 N . A wave with frequency 105 Hz and amplit

Romashka-Z-Leto [24]

The concept needed to solve this problem is average power dissipated by a wave on a string. This expression ca be defined as

$P = \frac{1}{2} \mu \omega^2 A^2 v$

Here,

$\mu$ = Linear mass density of the string

$\omega =$ Angular frequency of the wave on the string

A = Amplitude of the wave

v = Speed of the wave

At the same time each of this terms have its own definition, i.e,

$v = \sqrt{\frac{T}{\mu}} \rightarrow$ Here T is the Period

For the linear mass density we have that

$\mu = \frac{m}{l}$

And the angular frequency can be written as

$\omega = 2\pi f$

Replacing this terms and the first equation we have that

$P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2(\sqrt{\frac{T}{\mu}})$

$P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2 (\sqrt{\frac{T}{m/l}})$

$P = 2\pi^2 f^2A^2(\sqrt{T(m/l)})$

PART A ) Replacing our values here we have that

$P = 2\pi^2 (105)^2(1.8*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})$

$P = 0.2320W$

PART B) The new amplitude A' that is half ot the wavelength of the wave is

$A' = \frac{1.8*10^{-3}}{2}$

$A' = 0.9*10^{-3}$

Replacing at the equation of power we have that

$P = 2\pi^2 (105)^2(0.9*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})$

$P = 0.058W$

8 0

2 years ago

A cinder cone is formed from relatively ________ viscosity magma with a ________ gas content. low; high high; high low; low high

kenny6666 [7]

<span>A cinder cone is formed from relatively low viscosity magma with a high gas content. Cinder cones are formed by the volcanic ash, cinders that are formed around the volcanic vent. Cinder cones have a bowl shaped crater and the shape of the cinder cones depend on the ejected particles that formed the cinder.</span>

5 0

3 years ago

A cell of internal resistance 2 ohms supplies current to a 6 ohms resistor. What is the efficiency of the cell?. ​

A cell of internal resistance 2 ohms supplies current to a 6 ohms resistor. What is the efficiency of the cell?.