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WINSTONCH [101]
3 years ago
10

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How many neutrons are present in 4.4 gram of Co2​
Chemistry
1 answer:
sladkih [1.3K]3 years ago
6 0

Explanation:

hope it will help you Mark me as a brilliant

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If an isotope of oxygen has 8 protons, 10 neutrons, and 8 electrons, its mass number is_______.
melamori03 [73]

Answer:

mass number = 18

Explanation:

The mass number is the total amount of protons and neutrons in an atom. Therefore, if there are 8 protons and 10 neutrons, the mass number is 18 (8 + 10 = 18).

4 0
2 years ago
Use the definition of molarity to calculate the concentration of 12.34 g of CaSO4 completely dissolved in water, with a solution
Ede4ka [16]

Answer:

[CaSO₄] = 36.26×10⁻² mol/L

Explanation:

Molarity (M) → mol/L → moles of solute in 1L of solution

Let's convert the volume from mL to L

250 mL . 1L/1000 mL = 0.250L

We need to determine the moles of solute. (mass / molar mass)

12.34 g / 136.13 g/mol = 0.0906 mol

M → 0.0906 mol / 0.250L = 36.26×10⁻² mol/L

8 0
3 years ago
What is the minimum of acetic anhydride (102.1 g/mol) required to react completely with the 2.94 grams of salicylic acid? What v
Lady bird [3.3K]

Answer:

a) the minimun of acetic anhydride required for the  reaction is 2.175 g (CH3CO)2O

b) V acetic anhydride = 2.010 mL

Explanation:

  • balanced reaction:

      C6H4OHCOOH + (CH3CO)2O  ↔  C9H8O4 + C2H4O2

⇒ mol salicylic acid = 2.94 g C6H4OHCOOH * ( mol C6H4OHCOOH / 138.121 g ) = 0.0213 mol C6H4OHCOOH

⇒ mol acetic anhydride = 0.0213 mol C6H4OHCOOH * ( mol (CH3CO)2O /  mol  C6H4OHCOOH ) = 0.0213 mol (CHECO)2O

⇒ g acetic anhydride = 0.0213 mol * ( 102.1 g/mol ) = 2.175 g CH3CO)2O

b) V = 2.175 g (CH3CO)2 * ( mL / 1.082 g ) = 2.010 mL (CH3CO)2O

4 0
3 years ago
What is the product of 1.65 and 1.05 x 10-27
lilavasa [31]

Answer:

-<em>9</em><em>.</em><em>6</em><em>7</em><em>5</em>

Explanation:

<em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>m</em><em>e</em><em> </em><em>i</em><em>f</em><em> </em><em>i</em><em>m</em><em> </em><em>w</em><em>r</em><em>o</em><em>n</em><em>g</em><em>.</em><em>!</em><em>!</em><em> </em><em />

3 0
3 years ago
Read 2 more answers
Please help it’s due today I will give brainliest
Thepotemich [5.8K]

1st and 4th options are suitable answers, as these 2 changes are not exactly physical changes as it cant return back to original form and as well as its not cooling, so I feel its 1st and 4th options

7 0
3 years ago
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