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adell [148]
2 years ago
14

What is your design for an efficient commercial vehicle chassis that incorporates as many commercial truck components into its s

tructure as realistically possible? ​
Physics
1 answer:
Crank2 years ago
5 0

The design that would be used to make an efficient commercial vehicle chassis that has many realistic truck components is:

  • Strength
  • Adequate bending stiffness
  • Maximum stress
  • Deflection, etc

<h3>What is a Chassis Frame?</h3>

This refers to the main vehicle structure of a car that bears all the main stress that other components are attached to.

Hence, we can see that to make a good design for an efficient commercial vehicle chassis that has many realistic truck components, we would have to consider various factors such as handling maximum stress, maximum equilateral stress, and deflection.

Read more about chassis frame here:

brainly.com/question/15382293

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In a photoelectric effect experiment, electrons emerge from a copper surface with a maximum kinetic energy of1.10eVwhen light sh
V125BC [204]

5.610^-26 m  is closest to the wavelength of the light.

E=K.E - Work function

hc/λ=1.10-4.65

hc/λ=3.50

λ=hc/3.50

λ=6.626×10 −34J⋅s×3×10^8

λ=5.610^-26 m

Because the relationship between wave frequency and wavelength is inverse, gamma rays have extremely short wavelengths that are only a fraction of the size of atoms, whereas other wavelengths can reach as far as the universe. Regardless of the medium they travel through, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, even though this isn't always stated explicitly.

The wavelength of electromagnetic radiation affects its behavior. The speed of light is equal to wavelength times frequency. Frequency multiplied by the Planck constant equals energy. 1/wavelength is the wave number in cm. Along with the wavelengths of different parts of the electromagnetic spectrum, a rough estimation of the wavelength size is displayed.

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5 0
1 year ago
A child is riding a bike at a speed of 6m/s with a total kinetic energy of 1224J. If the mass of the child is 30kg, what is the
UkoKoshka [18]

Answer:

 Mass of bike = 38 kg.

Explanation:

Kinetic energy is given by the expression, KE = \frac{1}{2} mv^2, where m is the mass and v is the velocity.

Here speed of child riding bike = 6 m/s

Mass of child = 30 kg

Total kinetic energy = 1224 J

Let the mass of bike be, m kg

So, total mass of child and bike = (m + 30) kg

Substituting,

  1224 = \frac{1}{2}* (m+30)*6^2\\ \\ m+30=68\\ \\ m=38kg

So, mass of bike = 38 kg.

3 0
4 years ago
There is a seasaw that's holding two men. The seesaw has a length of 18m that can pivot from a point at its center. Man 1 has a
Alex

Answer:

Distance=  2.3864m

Explanation:

So that the balance is in equilibrium parallel to the floor, we must match the moment each man makes with respect to the pivot point.

In many cases the point of application of force does not coincide with the point of application in the body. In this case the force acts on the object and its structure at a certain distance, by means of an element that transfers that action of this force to the object.

This combination of force applied by the distance to the point of the structure where it is applied is called the moment of force F with respect to the point. The moment will attempt a rotation shift or rotation of the object. The distance from the force to the point of application is called the arm.

Mathematically it is calculated by expression:

M= F×d

The moment caused by the first man is:

M1= 75kg × (9.81m/s²) × 1.75m= 1287.5625 N×m

The moment caused by the second man must be equal to that caused by the first by which:

M2= 1287.5625 N×m= 55kg × (9.81m/s²) × distance ⇒

⇒distance= (1287.5625 N×m)/( (55kg × (9.81m/s²) )= 2.3864m

At this distance from the pivot point, the second should sit down so that the balance is balanced parallel to the ground.

3 0
3 years ago
A 40.0 kg beam is attached to a wall with a hi.nge and its far end is supported by a cable. The angle between the beam and the c
GalinKa [24]

The magnitude of the force that the beam exerts on the hi.nge will be,261.12N.

To find the answer, we need to know about the tension.

<h3>How to find the magnitude of the force that the beam exerts on the hi.nge?</h3>
  • Let's draw the free body diagram of the system using the given data.
  • From the diagram, we have to find the magnitude of the force that the beam exerts on the hi.nge.
  • For that, it is given that the horizontal component of force is equal to the 86.62N, which is same as that of the horizontal component of normal reaction that exerts by the beam on the hi.nge.

                           N_x=86.62N

  • We have to find the vertical component of normal reaction that exerts by the beam on the hi.nge. For this, we have to equate the total force in the vertical direction.

                           N_y=F_V=mg-Tsin59\\

  • To find Ny, we need to find the tension T.
  • For this, we can equate the net horizontal force.

                           F_H=N_x=Tcos59\\\\T=\frac{F_H}{cos59} =\frac{86.62}{0.51}= 169.84N

  • Thus, the vertical component of normal reaction that exerts by the beam on the hi.nge become,

                    N_y= (40*9.8)-(169.8*sin59)=246.4N

  • Thus, the magnitude of the force that the beam exerts on the hi.nge will be,

                 N=\sqrt{N_x^2+N_y^2} =\sqrt{(86.62)^2+(246.4)^2}=261.12N

Thus, we can conclude that, the magnitude of the force that the beam exerts on the hi.nge is 261.12N.

Learn more about the tension here:

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4 0
2 years ago
Read 2 more answers
What is Virtual Lab and what does people use it for and why they use it?
Dafna1 [17]

The Virtual Laboratory is an interactive environment for creating and conducting simulated experiments: a playground for experimentation. It consists of domain-dependent simulation programs, experimental units called objects that encompass data files, tools that operate on these objects

7 0
3 years ago
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