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Salsk061 [2.6K]
3 years ago
12

Solve for m2= F ---- m

Physics
1 answer:
Pie3 years ago
3 0
Don't think m has a
value
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How does weak background radiation coming from every direction in the sky support the big bang theory
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Option 1

It provides evidence of universe expansion

Explanation:

The Big Bang Theory actually explains the universe as originating from a single point, which expanded as billions of years went by.

The background radiation supports this theory in the sense that if the universe is expanding, this means that the universe is cooling and continuously losing heat, which results in background radiation

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Which of the following forces exists between objects even in the absence of direct physical contact
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A person jumps from the roof of a house 3.5-m high. When he strikes the ground below, he bends his knees so that his torso decel
Korvikt [17]

The force exerted on his torso by his legs during the deceleration is 4365 N.

<u>Explanation:</u>

Mass of the torso m=45kg

Height of the building s=3.5 m

Decelerating distance=0.71 m

when he jumps to the ground, the only acceleration is acceleration due to gravity g

<u>motion1 from top to ground </u>

initial velocity u=0

we have to calculate final velocity v using the following equation of motion.

v^2-u^2=2gs\\v^2-0^2=2\times 9.8\times3.5=68.6\\v=\sqrt{68.6} \\=8.3

use height of the building as the distance s as the jump from top to the ground is only described here.

<u>Motion 2 on the ground</u>

v=0

u=8.3(final  velocity of motion 1)

The deceleration after striking the ground can  be calculated from the equation of motion

v^2-u^2=2as\\\\a=v^2-u^2/2\times 0.71\\=0^2-8.3^2/0.71=97 m/s^2

The decelerating distance is used in the place of s since since the motion after hitting the ground is described in this case.

The equation of force is

F=ma\\=45\times 97=4365 N

6 0
3 years ago
Kevin jump straight up in the air to a height of 1 m at the top of his jump he has the potential energy of 1000 J answer the fol
NeTakaya

Answer:

1000N,4.48m/s

Explanation:

Height(h) = 1m

P. E = 1000J

P. E = mass x acceleration due to gravity x height

Acceleration due to gravity = 10m/s

P. E = mgh

Where weight = mg

P. E = weight x height

Weight = P. E / height

Weight = 1000 / 1

Weight. 1000N

b) as he leaves the ground P. E = K. E

P. E = 1/2 mv2

P. E = 1000 , mass = weight / 10

                      Mass =1000/10 = 100kg

P. E = 1/2 mv2

1000 = 1/2 x 100 x v2

Multiply both sides by 2

1000 x 2 = 100 x v2

V2 = 2000/ 100

V2 =20

Square root both sides

V = square root of 20

V = 4.48m/s

I hope this was helpful, Please mark as brainliest

4 0
3 years ago
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