Could be c because it matches the question
Answer:
Option 1
It provides evidence of universe expansion
Explanation:
The Big Bang Theory actually explains the universe as originating from a single point, which expanded as billions of years went by.
The background radiation supports this theory in the sense that if the universe is expanding, this means that the universe is cooling and continuously losing heat, which results in background radiation
The force exerted on his torso by his legs during the deceleration is 4365 N.
<u>Explanation:</u>
Mass of the torso m=45kg
Height of the building s=3.5 m
Decelerating distance=0.71 m
when he jumps to the ground, the only acceleration is acceleration due to gravity g
<u>motion1 from top to ground </u>
initial velocity u=0
we have to calculate final velocity v using the following equation of motion.

use height of the building as the distance s as the jump from top to the ground is only described here.
<u>Motion 2 on the ground</u>
v=0
u=8.3(final velocity of motion 1)
The deceleration after striking the ground can be calculated from the equation of motion

The decelerating distance is used in the place of s since since the motion after hitting the ground is described in this case.
The equation of force is

Answer:
1000N,4.48m/s
Explanation:
Height(h) = 1m
P. E = 1000J
P. E = mass x acceleration due to gravity x height
Acceleration due to gravity = 10m/s
P. E = mgh
Where weight = mg
P. E = weight x height
Weight = P. E / height
Weight = 1000 / 1
Weight. 1000N
b) as he leaves the ground P. E = K. E
P. E = 1/2 mv2
P. E = 1000 , mass = weight / 10
Mass =1000/10 = 100kg
P. E = 1/2 mv2
1000 = 1/2 x 100 x v2
Multiply both sides by 2
1000 x 2 = 100 x v2
V2 = 2000/ 100
V2 =20
Square root both sides
V = square root of 20
V = 4.48m/s
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