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Galina-37 [17]
2 years ago
15

Which of the following would cause the greatest decrease in gravitational force between the earth and the moon? an increase in t

he earth's mass an increase in the moon's mass an increase in the distance between the earth and the moon a decrease in the distance between the earth and the moon
Physics
1 answer:
Sphinxa [80]2 years ago
8 0
<span>a decrease in the distance between the earth and the moon</span>
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What do you get when you subtract the force of air resistance from the force<br> of gravity?
atroni [7]

Answer:

Net force

Explanation:

3 0
3 years ago
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In a historical movie, two knights on horseback start from rest 86 m apart and ride directly toward each other to do battle. Sir
Harlamova29_29 [7]

Answer:

Relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.

Explanation:

Let the distance covered by Sir George be S_{1}

and the distance covered by Sir Alfred be S_{2}

Since the knights collide, hence they must have traveled for the same amount of time just before collision

From one of the equations of motion for linear motion

S = ut + \frac{1}{2}at^{2}

Where S is the distance traveled

u is the initial velocity

a is the acceleration

and t is the time

For Sir George,

S = S_{1}

u = 0 m/s (Since they start from rest)

a =0.21 m/s²

Hence,

S = ut + \frac{1}{2}at^{2} becomes

S_{1}  = (0)t + \frac{1}{2}(0.21)t^{2}\\S_{1}  = 0.105 t^{2}\\

t^{2} = \frac{S_{1}}{0.105}

Now, for Sir Alfred

S = S_{2}

u = 0 m/s (Since they start from rest)

a =0.26 m/s²

Hence,

S = ut + \frac{1}{2}at^{2} becomes

S_{2}  = (0)t + \frac{1}{2}(0.26)t^{2}\\S_{2}  = 0.13 t^{2}\\

t^{2} = \frac{S_{2}}{0.13}

Since, they traveled for the same time, t just before collision, we can write

\frac{S_{1}}{0.105}= \frac{S_{2}}{0.13}

Since, the two nights are 86 m apart, that is, the sum of the distances covered by the knights just before collision is 86 m. Then we can write that

S_{1} + S_{2} = 86 m

Then, S_{2} = 86 - S_{1}

Then,

\frac{S_{1}}{0.105}= \frac{S_{2}}{0.13} becomes

\frac{S_{1}}{0.105}= \frac{86 -S_{1}}{0.13}

0.13{S_{1}}= 0.105({86 -S_{1}})\\0.13{S_{1}}= 9.03 - 0.105S_{1}}\\0.13{S_{1}} + 0.105S_{1}}= 9.03 \\0.235{S_{1}} = 9.03\\{S_{1}} =\frac{9.03}{0.235}

S_{1} = 38.43 m

∴ Sir George covered a distance of 38.43 m just before collision.

Hence, relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.

6 0
3 years ago
The force that one massive object excerts to attract another object is called
Bogdan [553]
The force that one massive object exerts  to attract another object is called gravity or gravitational pull.
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Which statement best compares the properties of compounds and elements that the compounds contain?
Agata [3.3K]
A compound is formed due to the chemical combination or chemical reaction between two or more elements. The elements forming a compound cannot be separated by physical means. The properties of the compound is different from the properties of the elements forming it.

Based on this, the answer would be:
They are different.
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In scientific terms, how is power related to work?
Nuetrik [128]
C. the rate at which work is done. hope i helped!
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