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Galina-37 [17]
3 years ago
15

Which of the following would cause the greatest decrease in gravitational force between the earth and the moon? an increase in t

he earth's mass an increase in the moon's mass an increase in the distance between the earth and the moon a decrease in the distance between the earth and the moon
Physics
1 answer:
Sphinxa [80]3 years ago
8 0
<span>a decrease in the distance between the earth and the moon</span>
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Answer: The answer is D!

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The fire alarm goes off, and a 75 kg firefighter slides down a pole with a constant acceleration of a = 6 m/s square. What is th
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Answer:

450N

Explanation:

Given data

Mass m= 75kg

Acceleration= 6m/s^2

From the Newtons first law, F=ma

substitute

F=75*6

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honor physics The velocity of a 200 kg object is changed from 5 m/s to 25 m/s in 50 seconds by an applied constant force. a. Wha
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(a) 4000 kgm/s.

(b) 80 N

Explanation:

(a) Change in momentum: This can be defined as the product of the mass of a body and its change in velocity. The S.I unit of impulse is Ns or kgm/s

Mathematically, Change in momentum is expressed as

ΔM = mΔv ..................................... Equation 1

Where ΔM = change in momentum, m = mass of the object, Δv = change in velocity = v₂ - v₁

Given: m = 200 kg, Δv = v₂ - v₁ = 25-5 = 20 m/s.

Substituting into equation 1

ΔM = 200(20)

ΔM = 4000 kgm/s.

Hence the change in momentum = 4000 kgm/s

(b)

Force: This can be defined as the ratio of the change in momentum of a body to the time required for the change.

F = ΔM/t.............................. Equation 2

Where F = force, ΔM = change in momentum, t = time.

Given: ΔM  = 4000 kgm/s, t = 50 second.

Substituting into equation 2

F = 4000/50

F = 80 N.

Hence the force  = 80 N

7 0
3 years ago
A scientist makes a device to catch baseballs. A long bar of total mass 2.2kg and length 1.2m is fixed at its center. It catches
Valentin [98]

Answer:

ωf = 4.53 rad/s

Explanation:

By conservation of the angular momentum:

Ib*ωb = (Ib + Ic)*ωf

Where

Ib is the inertia of the ball

ωb is the initial angular velocity of the ball

Ic is the inertia of the catcher

ωf is the final angular velocity of the system

We need to calculate first Ib, Ic, ωb:

Ib = mb*(L/2)^2=0.15*(1.2/2)^2=0.054 kg.m^2

Ic = mc/12*L^2=2.2/12*1.2^2=0.264 kg.m^2

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Now, ωf will be:

\omega f = \frac{Ib*\omega b}{Ib + Ic}  = 4.53rad/s

8 0
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