The pressure exerted by a fluid solely relies on the depth or height of the fluid, its density, and the gravitational constant. These three are related in the equation:
Pressure = density x g x height
In the problem, point A is within the block inside the tank. The water above the block is assumed to be 0.6 meters. This gives a point A pressure of:
P = 1000 kg/m^3 * 9.81 m/s^2 * 0.6 m = 5,886 Pa or 5.88KPa
Answer:
Gravity provides a downward force, resulting in the diver going downward. They speed up like any falling object would, the pull of gravity is a dominant force. (There is a drag force – as a result of moving through the air.)
Answer:the rate changes during the position of the object
Explanation:so there is no object that has the same rate but unless it is a specific one like a care but it changes during the position of the object
Answer:
the coefficient of volume expansion of the glass is 
Explanation:
Given that:
Initial volume of the glass flask = 1000 cm³ = 10⁻³ m³
temperature of the glass flask and mercury= 1.00° C
After heat is applied ; the final temperature = 52.00° C
Temperature change ΔT = 52.00° C - 1.00° C = 51.00° C
Volume of the mercury overflow = 8.50 cm^3 = 8.50 × 10⁻⁶ m³
the coefficient of volume expansion of mercury is 1.80 × 10⁻⁴ / K
The increase in the volume of the mercury = 10⁻³ m³ × 51.00 × 1.80 × 10⁻⁴
The increase in the volume of the mercury = 
Increase in volume of the glass = 10⁻³ × 51.00 × 
Now; the mercury overflow = Increase in volume of the mercury - increase in the volume of the flask
the mercury overflow = 






Thus; the coefficient of volume expansion of the glass is 
Answer:
The value is
Explanation:
From the question we are told that
The power output from the sun is 
The average wavelength of each photon is 
Generally the energy of each photon emitted is mathematically represented as

Here h is the Plank's constant with value 
c is the speed of light with value 
So
=>
Generally the number of photons emitted by the Sun in a second is mathematically represented as

=> 
=>