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Katena32 [7]
3 years ago
7

A 6.2 kg object moving in the +x direction at 5.3 m/s collides head-on with an 7.8 kg object moving in the −x direction at 2.5 m

/s.
Find the final velocity of each mass for each of the following situations. (Take the positive direction to be +x.)
(a) The bodies stick together.
1 m/s (6.2 kg mass)
2 m/s (7.8 kg mass)
(b) The collision is elastic.
3 m/s (6.2 kg mass)
4 m/s (7.8 kg mass)
(c) The 6.2 kg body is at rest after the collision.
5 m/s (6.2 kg mass)
6 m/s (7.8 kg mass)
(d) The 7.8 kg body is at rest after the collision.
7 m/s (6.2 kg mass)
8 m/s (7.8 kg mass)
(e) The 6.2 kg body has a velocity of 4.0 m/s in the -x direction after the collision.
9 m/s (6.2 kg mass)
10 m/s(7.8 kg mass)
Physics
1 answer:
Crank3 years ago
8 0

Answer:

10ms kg 88.2

Explanation:

Toook test

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The speed of a proton after it accelerates from rest through a potential difference of 350 V is 25.86 \times 10^4 ~m/s.

Initial velocity of the proton u = 0

Given potential difference \Delta V = 350V

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Since the proton is accelerating through a potential difference, proton's potential energy will change with time. The potential energy of a particle of charge q when accelerated with a potential difference \Delta V is,

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Due to Work-Energy Theorem and Conservation of Energy - <em>If there is no non-conservative force acting on a particle then loss in Potential energy  P.E must be equal to gain in Kinetic Energy K.E</em> i.e

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change in Potential Energy \implies \Delta U = q\Delta V

from conservation of energy,

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so,         v = \sqrt{\frac{2\times 350 \times 1.6\times 10^{-19}}{1.67 \times 10^{-27}}

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To read more about the conservation of energy, please go to brainly.com/question/14668053

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