Given :
An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west.
It starts at the 14-inch mark, crawls to the 20-inch mark, then moves to the 16-inch mark.
To Find :
The total distance the ant traveled.
Solution :
Total distance travelled by ant = (distance between 14 and 20 inch mark) +
(distance between 20 and 16 inch mark)
Total distance = (20-14 ) + ( 20-16) = 6 + 4 = 10 inch.
Therefore, total distance the ant traveled is 10 inch.
Hence, this is the required solution.
V = final velocity
u = initial velocity
a = acceleration
s = displacement
Take downward direction as positive.
v^2 = u^2 + 2as
v^2 = 0.8^2 + 2(1.6)(5.5)
v^2 = 18.24
v = 4.27 m/s
B. Conductors allow electricity to go through them only. Such as copper etc.
Noise could be defined as electromagnetic fields that affect analog signals that are constantly changing. This process does not occur in a similar way with digital signals, which have fixed electrostatic pulses (For this reason they are able to withstand 'noise' because the power of these signals are much stronger than the power coming from noise).
That phenomenon does not happen with the analog signals which have a variable intensity and become vulnerable to any electronic noise interference.
When very high electromagnetic fields are generated, the waves of the analog signal cannot be perceived which causes problems in the transmitted signal (making it unintelligible to the receiver)
Answer:
Frequency will not change.
Explanation:
As you know, Time period 'T' = 2π x √(L/g)
where,
L= the length of the pendulum
g= acceleration due to gravity
and Frequency 'f' is the reciprocal of period.f=1/T
From above, we can conclude that frequency is not dependent on mass.
It depends upon the acceleration due to gravity 'g' and the length of the pendulum 'L'
So, if a hole in the ball allowed water to slowly leak out, frequency would not change
