How does noise affect signals? what happens if the level of noise becomes too high relative to the strength of the signal.

1 answer:

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Noise could be defined as electromagnetic fields that affect analog signals that are constantly changing. This process does not occur in a similar way with digital signals, which have fixed electrostatic pulses (For this reason they are able to withstand 'noise' because the power of these signals are much stronger than the power coming from noise).

That phenomenon does not happen with the analog signals which have a variable intensity and become vulnerable to any electronic noise interference.

When very high electromagnetic fields are generated, the waves of the analog signal cannot be perceived which causes problems in the transmitted signal (making it unintelligible to the receiver)

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Practice Exercises Name: : Billy-Joe stands on the Talahatchee Bridge kicking stones into the water below a) If Billy-Joe kicks

babymother [125]

Answer:

a) The answer is 11,7m

b) The time it takes to fall will be shorter

Explanation:

We will use the next semi-parabolic movement equations

$H=Hi+Viy*t+1/2*g*t$

$X=Xi+Vx*t$

Where g(gravity acceleration)=9,81m/s^2

Also Xi, Hi and Viy are zero, as the stones Billy-Jones is kicking stay still before he moves them, so we take that point as the reference point

The first we must do is to find how much time the stones take to fall, this way:

$t=(5.40m)/(3.50m/s)$

Then t=1,54s

After that we need to replace t to find H, this way

$H=(1/2)*(9,81m/s^2)*(1,54s)^2$

Then H=11,7m

b) The stones will fall faster as the stones will be kicked harder, it will cause the stones move faster, it means, more horizontal velocity. In order to see it better we could assume the actual velocity is two times more than it is, so it will give us half of the time, this way:

$t=(5,40m)/(2*3,50m/s)$