Please add you assignment.
Answer:
answer will be 3.08 mol ig.....
Answer:
7.86 g/cm³
Explanation:
11.0 kg = 11,000 g
The density in g/cm³ is ...
(11,000 g)/(1,400 cm³) = 7.86 g/cm³
The moles of oxygen that are needed to produce 13.7 moles of carbon dioxide is 21.17 moles of Oxygen
<u><em>calculation</em></u>
2 C₆H₁₂O + 17 O₂ → 12 CO₂ +12 H₂O
The moles of O₂ is determined using the mole ratio
that is for given equation above O₂ : Co₂ is 17 :12
therefore the moles of O ₂= 13.7 moles x 17/12 =21.17 moles
