Question: The question is not complete. Find below the complete question and the answer.
Alab group was supposed to make 14 mL of a 36% acid solution by mixing a 20% solution, a 26% solution, and a 42% solution. However, the 20% solution was mislabeled, and was actually a 10% solution, so the lab group ended up with 14 mL of a 34% acid solution, instead. If the augmented matrix that represents the system of equations is given below, what are the volumes of the solutions that should have been mixed? mL
Volume of 20% solution= ?
Volume of 26% solution = ?
Volume of 42% solution= ? Round to the nearest whole number ml
Answer:
Volume of 20% solution= 3 mL
Volume of 26% solution = 1 mL
Volume of 42% solution= 10 mL
Explanation:
Find attached of the calculations.
Answer:
The coefficient that should be inserted in front of chlorine is 2
Explanation:
Sn + 2Cl₂ → SnCl₄
As we have 4 atoms of chlorine in product side, we need 4 Cl in reactant side.
Chlorine is a diatomic atom, so if we have 2 mol of it, we are having 4 atoms of Cl.
The law of conservation of mass must be respected in every chemical equation
Answer: If a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.
Explanation:
The relation between energy and wavelength is as follows.
![E = \frac{hc}{\lambda}\\](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D%5C%5C)
This means that energy is inversely proportional to wavelength.
As it is given that energy of a hydrogen atom and a helium atom is same.
Let us assume that
. Hence, relation between their wavelengths will be calculated as follows.
... (1)
... (2)
Equating the equations (1) and (2) as follows.
![E_{hydrogen} = E_{helium} = E'\\\frac{hc}{\lambda_{hydrogen}} = \frac{hc}{\lambda_{helium}} = E'\\\lambda_{helium} = \lambda_{hydrogen} = E'](https://tex.z-dn.net/?f=E_%7Bhydrogen%7D%20%3D%20E_%7Bhelium%7D%20%3D%20E%27%5C%5C%5Cfrac%7Bhc%7D%7B%5Clambda_%7Bhydrogen%7D%7D%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda_%7Bhelium%7D%7D%20%3D%20E%27%5C%5C%5Clambda_%7Bhelium%7D%20%3D%20%5Clambda_%7Bhydrogen%7D%20%3D%20E%27)
Thus, we can conclude that if a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.
<span>Get a periodic table of elements. ...Find your element on the periodic table. ...Locate the element's atomic number. ...Determine the number of electrons. ...Look for the atomic mass of the element. ...<span>Subtract the atomic number from the atomic mass.</span></span>
The metal properties that make up electrical wires are conductivity and ductility. Conductivity is important for free electrons to flow, hence electricity. Ductility is as well integral for strips to be formed, but with ample strength that does not break the material.