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grin007 [14]
2 years ago
8

Which of the following is an oxidation-reduction reaction?

Chemistry
1 answer:
Hatshy [7]2 years ago
8 0

B. The chemical reaction that represents oxidation - reduction reaction is CaCO3(s) → CaO(s) + CO2(g).

<h3>Oxidation reduction reaction</h3>

In oxidation reduction reaction, the oxidizing agent is reduced while reducing agent is oxidized.

<h3>In the chemical equation below;</h3>

CaCO3(s) → CaO(s) + CO2(g)

Calcium (ca) is oxidized calcium (II) ion while the carbon (IV) oxide is reduced carbon (IV) oxide.

Thus, the chemical reaction that represents oxidation - reduction reaction is CaCO3(s) → CaO(s) + CO2(g).

Learn more about oxidation reduction reaction here: brainly.com/question/4222605

#SPJ1

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Why is the formation of water a synthesis reaction?
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Explanation:

A synthesis reaction: It is defined as a kind of reaction where one and more than one reactant attached and creates an individual product.

The formation of the water is an example of a synthesis reaction because here more than one reactants combine and create a single product (water). Water formation occurs when 2 hydrogens and an oxygen share electrons through covalent bonds.

2H + O ----> H2O.

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If kc = 7.04 × 10-2 for the reaction: 2 hbr(g) ⇌h2(g) + br2(g), what is the value of kc for the reaction: 1/2 h2(g) + 1/2 br2 ⇌h
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At the first reaction when 2HBr(g) ⇄ H2(g) + Br2(g)
So Kc = [H2] [Br2] / [HBr]^2
7.04X10^-2 = [H2][Br] / [HBr]^2

at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root: 
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769 
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The reaction between an organic acid and an alcohol produces
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If it’s a carboxylic acid with an alcohol then it’ll form an ester and water.
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