Which of the following is an oxidation-reduction reaction?

Chemistry

1 answer:

Hatshy [7]2 years ago

8 0

B. The chemical reaction that represents oxidation - reduction reaction is CaCO3(s) → CaO(s) + CO2(g).

<h3>Oxidation reduction reaction</h3>

In oxidation reduction reaction, the oxidizing agent is reduced while reducing agent is oxidized.

<h3>In the chemical equation below;</h3>

CaCO3(s) → CaO(s) + CO2(g)

Calcium (ca) is oxidized calcium (II) ion while the carbon (IV) oxide is reduced carbon (IV) oxide.

Thus, the chemical reaction that represents oxidation - reduction reaction is CaCO3(s) → CaO(s) + CO2(g).

Learn more about oxidation reduction reaction here: brainly.com/question/4222605

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50.g of NaNO3 was dissolved in 1250 mL of water. what is the molality of the solution? [ Molar mass of NaNO3 = 85 g/mol

Viefleur [7K]

Answer:

Approximately $0.47\; \rm mol \cdot L^{-1}$ (note that $1\; \rm M = 1 \; \rm mol \cdot L^{-1}$ .)

Explanation:

The molarity of a solution gives the number of moles of solute in each unit volume of the solution. In this $\rm NaNO_3$ solution in water,

Let $n$ be the number of moles of the solute in the whole solution. Let $V$ represent the volume of that solution. The formula for the molarity $c$ of that solution is:

$\displaystyle c = \frac{n}{V}$ .

In this question, the volume of the solution is known to be $1250\; \rm mL$ . That's $1.250\; \rm L$ in standard units. What needs to be found is $n$ , the number of moles of $\rm NaNO_3$ in that solution.

The molar mass (formula mass) of a compound gives the mass of each mole of units of this compound. For example, the molar mass of $\rm NaNO_3$ is $85\; \rm g \cdot mol^{-1}$ means that the mass of one mole of

$\displaystyle n = \frac{m}{M}$ .

For this question,

$\begin{aligned}&n\left(\mathrm{NaNO_3}\right) \\ &= \frac{m\left(\mathrm{NaNO_3}\right)}{M\left(\mathrm{NaNO_3}\right)}\\&= \frac{50\; \rm g}{85\; \rm g \cdot mol^{-1}} \\& \approx 0.588235\; \rm mol\end{aligned}$ .