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WINSTONCH [101]
2 years ago
10

A sample of He gas (2.35 mol) occupies 57.9 L at 300.0 K and 1.00 atm. The volume of this sample is __________ L at 423 K and 1.

00 atm.
Chemistry
1 answer:
tiny-mole [99]2 years ago
4 0

Considering the combined law, the volume of the sample is 81.639 L at 423 K and 1.00 atm.

<h3>Charles's law</h3>

Charles's law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles's law states:

\frac{V}{T}=k

<h3>Boyle's law</h3>

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.

Mathematically, this law is expressed as:

P×V= k

<h3>Gay-Lussac's law</h3>

Gay-Lussac's law establishes the relationship between the temperature and pressure of a gas when the volume is constant. This law says that the pressure of a gas is directly proportional to its temperature: if the temperature increases, the pressure will increase, while if the temperature decreases, the pressure will decrease.

Mathematically, Gay-Lussac's law states:

\frac{P}{T}=k

<h3>Combined law equation</h3>

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{VxP}{T}=k

Considering an initial state 1 and a final state 2, it is fulfilled:

\frac{V1xP1}{T1}=\frac{V2xP2}{T2}

<h3>Volume of the sample</h3>

In this case, you know:

  • V1= 57.9 L
  • P1= 1 atm
  • T1= 300 K
  • V2= ?
  • P2= 1 atm
  • T2= 423 K

Replacing in combined law equation:

\frac{57.9 Lx1 atm}{300 K}=\frac{V2x1 atm}{423 K}

Solving:

V2= \frac{423 K}{1 atm} \frac{57.9 Lx1 atm}{300 K}

<u><em>V2= 81.639 L</em></u>

Finally, the volume of the sample is 81.639 L at 423 K and 1.00 atm.

Learn more about combined law equation:

brainly.com/question/4147359

#SPJ1

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A 10.0 ml portion of 0.010 m hcl is diluted by adding it to100.0 ml of water. what is the ph of the solution
Volgvan

From the calculation, the pH of the solution after dilution is 3.

<h3>What is the pH?</h3>

The pH is the hydrogen ion concentration of the solution. Now we know that;

C1 =  0.010 m

V1 = 10.0 ml

V2 = 10.0 ml + 100.0 ml = 110 ml

C2 = ?

C1V1 = C2V2

C2 = C1V1 /V2

C2 =  0.010 m  * 10.0 ml / 110 ml

C2 = 0.00091 M

pH = -log[0.00091 M]

pH = 3

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Explanation:

a) Volume of the gas nRT / P

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