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Marina CMI [18]
3 years ago
11

In a classic experiment using pea shape, Mendel conducted two separate genetic crosses. In the first cross the parent plants wer

e “true breeding” for pea shape; one had round peas ( R ) and the other had wrinkled (r). The first cross produced a filial 1 generation of all round peas. In the second cross, Mendel bred plants from the filial 1 generation. This cross produced different results. Out of approximately 1000 plants, about 75% were round and 25% were wrinkled. From these experiments, Mendel developed four hypotheses. They include all but ___________. A. One heritable factor may be dominant and mask the other factor. B. Any organism that "shows" a heritable factor must be homozygous.
Eliminate C. An organism has two "heritable factors", now called genes, one from each parent.
D. sperm or egg carries only one heritable factor for each trait in the offspring.
Chemistry
2 answers:
Ivanshal [37]3 years ago
7 0
B. Any organism that "shows" a heritable factor must be homozygous. 

Let's go through all choices:
A. TRUE! One heritable factor may be dominant and mask the other factor called recessive.
B. FALSE! Heterozygous organism can "show" a trait as well. If there is one dominant and one recessive form, a dominant form will mask it and dominant trait will be expressed. 
C. TRUE! An organism gets one form of the gene from the mother, and one from the father.
D. TRUE! That's why sperm or egg are called haploid.
lyudmila [28]3 years ago
4 0

Answer:

A) one heritable factor may be dominant and mask the other factor

Explanation:

any organism that shows a heritable factor must be homozygous.  Mendel did not know  or use terms such as genes, alleles, or homozygous versus heterozygous.

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A person's blood type is determined by the presence and absence of specific antigens on the cell membrane. Which of these would
sukhopar [10]

Answer:

C - no antibodies

Explanation:

I dont think there is any blood type without antibodies

5 0
3 years ago
Question 43 please. i’m not sure if i got the right answer
hram777 [196]

a) The reaction is exothermic since the overall enthalpy change is negative. this means that the system has lost energy to the environment, namely, the apparatus and due to drought.

b) We first calculate the number of moles in 3.55 grams of magnesium.

number of moles= mass/ atomic mass

                            =3.55/24

                            =0.1479 moles(to 4sf)

now, if 2 moles of magnesium give -1204kJ

        How much energy is given by 0.1479 moles

       = (0.1479×-1204kJ)

        =-89.0358kJ (don't forget the negative sign)

c) two molesof MgO produces -1204kJ of energy

then -234kJ will be produced by

=(-234kJ×2moles)/1204kJ

=0.3887moles

one mole of MgO weighs 24+16=40

therefore the mass produced is 0.3887moles×40=15.548grams

(d) we first find the number of moles of MgO in 40.3 grams

number of moles=mass/RFM

=40.3g/40= 1.0075moles

if 2 moles of MgO give 1204 kJ then decomposing 1.0075 moles requires

(1.0075 moles×1204kJ)/2=606.515kJ

4 0
3 years ago
Different kinds of wood have different densities. The density of american white oak wood is generally 0.77 g/cm3. If Jim grabs a
mixas84 [53]

Answer:

m= 29.645 g

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

density of wood = 0.77 g/cm³

volume= 38.5 cm³

mass= ?

Solution:

d= m/v

m= d × v

m= 0.77 g/cm³× 38.5 cm³

m= 29.645 g

7 0
3 years ago
A sample of 9.00 grams of aluminum metal is added to an excess of hydrochloric acid. The volume of hydrogen gas produced at stan
marysya [2.9K]

Answer:

The volumen of hydrogen (H) is 11.22 L

Explanation:

The balanced reaction between the aluminum (Al) and the hydrochloric acid (HCl) is:

2Al(s) + 6HCl(l) --> 2AlCl3(ac) + 3H2(g)

It is a reduction-oxidation reaction.

At the beginning we have 9.00 grams of Al what represents an certain amount of moles. Then, we know the molar mass of Al is 26.9815 g/mol, so the moles content in 9.00 g of Al are :

9.00 g Al * (1 mol Al / 26.9815 g Al)= 0.33356 mol Al

Now, we have to conisdered the molar relation between the Al and H2, according to the balanced reaction performed above. That is 2:3 (Al:H2)

Then,

0.33356 mol Al * (3 mol H2/  2mol Al) = 0.50034 mol H2

In this point, we can considered the H2 like a noble gas, because the question ask for standard temperature and pressure (0° C= 273.15K and 1 atm).

Let us remember the noble gases equation

PV=nRT

P: pressure

V: Volumen

n: number of moles

R: gases constant

T: temperature

For the volumen, the equation is:

V= (nRT/P)

Now: V= (0.50034 mol * 0.0821 (L*atm/K*mol) * 273.15 K)/ (1 atm)

         V= 11.22 L

3 0
3 years ago
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