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viktelen [127]
2 years ago
13

A geometric seqerence 1.5, -3, 6, -12 .... How many regative terms in the sequencs greater than

Mathematics
1 answer:
Leno4ka [110]2 years ago
4 0

The total negative terms are 4 which are greater than -6000 if the geometric sequence 1.5, -3, 6, -12 ... with a common ratio -3.

<h3>What is a sequence?</h3>

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have:

A geometric sequence 1.5, -3, 6, -12 ....

The common ratio r = -3/1.5 = -2

1.5, -3.6, 6, -12, 36, -108, 324, -972, 2916, -8748

The total negative terms = 4

Thus, the total negative terms are 4 which are greater than -6000 if the geometric sequence 1.5, -3, 6, -12 ... with a common ratio -3.

Learn more about the sequence here:

brainly.com/question/21961097

#SPj1

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Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.<br> r = 9 sin 7θ
boyakko [2]

Answer:

The given function symmetric about the y-axis.

Step-by-step explanation:

The given function is

r=9\sin 7\theta                .... (1)

1. Symmetry about the x-axis: If the point (r, θ ) lies on the graph, then the point  (r,-θ ) or (-r, π - θ ) also lies on the graph.

2. Symmetry about the y-axis: If the point (r, θ ) lies on the graph, then the point (r,π - θ ) or (-r, -θ ) also lies on the graph.

3. Symmetry about the origin: If the point (r, θ ) lies on the graph, then the point (-r, θ ) or (r, π + θ ) also lies on the graph.

Put (r, -θ ) in the given function.

r=9\sin 7(-\theta)=-9\sin 7\theta=-r\neq r

Therefore it is not symmetric about x-axis.

Put (-r, -θ ) in the given function.

-r=9\sin 7(-\theta)=-9\sin 7\theta=-r

Therefore it is symmetric about y-axis.

Put (-r,θ ) in the given function.

-r=9\sin 7(\theta)=r\neq -r

Therefore it is not symmetric about the origin.

3 0
3 years ago
N&lt;2^2. mathematical induction​
Dmitry [639]
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Inequality Form:
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Interval Notation:
(-, 4)


God bless you have a beautiful blessed day and I hope this makes it!
8 0
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