7. Explain how magnetic potential energy can be transformed into kinetic energy. (1 point)

1 answer:

5 0

The potential energy by the magnetic field can turn into kinetic energy once the field is moving from the S pole to the N pole when it reaches the N pole it is potential energy when it exits the S pole it is kinetic energy.

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In the first paragraph, the words "disrobed," "unveiling" and<br> "deconstructed" primarily serve to

Solnce55 [7]

Complete Question:

In the first paragraph, the words “disrobed,” “unveiling” and “deconstructed” primarily serve to (a) highlight the negative connotations that laser technology currently has, (b) emphasize the extensive reach of laser technology; (c) demonstrate the inherently unknowable characteristics of objects, even with laser technology; (d) implicitly compare lasers to other forms of technology

Answer:

(b) emphasize the extensive reach of laser technology;

Explanation:

The use of the word disrobed and deconstructed from the passage emphasizes the extensive reach of laser technology. Even without looking up the dictionary meaning of the two words, one can easily deduce that the passage is a pro-laser technology one.

The passage presents the use of the laser technology in solar exploration.
It also show its use by ecologists.

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8 0

3 years ago

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mestny [16]

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3 years ago

Ammonia is formed according to the reaction below. A chemist mixes 21 grams of nitrogen gas and 18 grams of hydrogen gas in a 2.

Rama09 [41]

Answer : The mass of hydrogen gas consumed will be, 4.5 grams

Explanation : Given,

Mass of $N_2$ = 21 g

Mass of $H_2$ = 18 g

Molar mass of $N_2$ = 28 g/mole

Molar mass of $H_2$ = 2 g/mole

First we have to calculate the moles of $N_2$ and $H_2$ .

$\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{21g}{28g/mole}=0.75moles$

$\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}=\frac{18g}{2g/mole}=9moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the given balanced reaction, we conclude that

As, 1 mole of $N_2$ react with 3 moles of $H_2$

So, 0.75 moles of $N_2$ react with $3\times 0.75=2.25$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $N_2$ is a limiting reagent because it limits the formation of product.

The moles of hydrogen gas consumed = 2.25 mole

Now we have to calculate the mass of hydrogen gas consumed.

$\text{Mass of }H_2=\text{Moles of }H_2\times \text{Molar mass of }H_2$