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Salsk061 [2.6K]
3 years ago
13

why do you think you can find silver and gold on their own in rocks but calcium and magnesium are combined with other elements t

o make compounds such as calcium carbonate and magnesium sulfate?​
Chemistry
2 answers:
katrin [286]3 years ago
4 0

Explanation:

Silver and Gold belong to a special group of metals known as the native metals. They are found naturally on their own and not in combined form in rocks.

  • These metals are found uncombined because they are unreactive.
  • They prefer to alloy with themselves.
  • Calcium and magnesium on the other hand are reactive metals.
  • The unreactivity of these metals makes them uncombined in nature.
aniked [119]3 years ago
4 0

ihsusbydnuhzkuhd nuziw

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What happens as thermal energy is transferred from the core to the mantle
musickatia [10]
It gets hotter because the core is the outside of the eath and the mantel is the more inside/hope i helped
7 0
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Alkanes are hydrocarbons containing only single bonds. Acyclic alkanes have carbon atoms arranged in chains, whereas cycloalkane
sashaice [31]

Answer:

156 Hydrogen atoms

Explanation:

<u>Any acyclic alkane has a molecular formula that can be expressed as</u>:

CₙH₂ₙ₊₂

Where <em>n</em> is any integer and the number of carbon atoms. For example, Propane has 3 carbon atoms, this means it would have [2*3+2] 8 hydrogen atoms, resulting with a formula of C₃H₈.

An acyclic alkane with 77 carbon atoms would thus have:

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4 0
3 years ago
Which kind of covalent bond has unequal sharing of electrons
lutik1710 [3]

Polar.

Polar bonds have unequal sharing electrons while nonpolar, the opposite, has equal sharing electrons. This is a tactic typically used to determine whether or not a compound or element itself is polar or nonpolar.

Hope this helps!

7 0
3 years ago
Read 2 more answers
A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0
3 years ago
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