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andriy [413]
3 years ago
10

How many d and f orbitals total are present in the n = 4 shell of a hydrogen atom? Enter your answer as a whole number.

Chemistry
1 answer:
sashaice [31]3 years ago
4 0

Answer:

12 orbitals

Explanation:

The suborbital = d orbital.

n = 4

The orbital is 4d.

There are 5 degenerate orbitals of d orbitals. Thus m value, -2, -1, 0, +1, +2 .

Thus, number of orbitals = 5

The suborbital = f orbital.

n = 4

The orbital is 4f.

There are 7 degenerate orbitals of f orbitals. Thus m value, -3, -2, -1, 0, +1, +2, +3

Thus, number of orbitals = 7

Total number of orbitals = 7 + 5 = 12

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Rasek [7]

Answer:

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Explanation:

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6 0
3 years ago
PLEASE HELP ME!!! ASAP
shtirl [24]

Answer:

Theoretical yield of the reaction = 34 g

Excess reactant is hydrogen

Limiting reactant is nitrogen

Explanation:

Given there is 100 g of nitrogen and 100 g of hydrogen

Number of moles of nitrogen = 100 ÷ 28 = 3·57

Number of moles of hydrogen = 100 ÷ 2 = 50

Reaction between nitrogen and hydrogen yields ammonia according to the following chemical equation

N2 + 3H2 → 2NH3

From the above chemical equation for every mole of nitrogen that reacts, 3 moles of hydrogen will be required and 2 moles of ammonia will be formed

Now we have 3·57 moles of nitrogen and therefore we require 3 × 3·57 moles of hydrogen

⇒ We require 10·71 moles of hydrogen

But we have 50 moles of hydrogen

∴ Limiting reactant is nitrogen and excess reactant is hydrogen

From the balanced chemical equation the yield will be 2 × 3·57 moles of ammonia

Molecular weight of ammonia = 17 g

∴ Theoretical yield of the reaction = 2 × 3·57 × 17 = 121·38 g

5 0
4 years ago
1 Which of the following is an example of periodicity?
Mademuasel [1]

Answer:

A:UNDERSTANDING CONCEPTS PART A 13) Which of the following is an example of periodicity? A) eating breakfast

8 0
3 years ago
H₃C-Ç=CCH₃<br>сна сHз (what is the name of this <br> chemical formula)​
algol [13]

Answer:2,3 -dimethyl-2-butenr

Explanation:

3 0
3 years ago
What is the coefficient for hydrogen in the balanced equation for the reaction of solid molybdenum(iv) oxide with gaseous hydrog
anastassius [24]

The  coefficient  for hydrogen  in  the  balanced  equation   of solid  molybdenum(iV)  oxide  with gaseous  hydrogen  is  2


 Explanation

Coefficient   is defined  to  as  a number  in front   of a chemical formula in a  balanced chemical equation.

   The  reaction   of   molybdenum (iv) oxide  with  gaseous  hydrogen  is  as below,


MoO2  + 2 H2→  Mo  +2 H2O

From   balanced equation above  the coefficient   for  H2  is  2  since  the number in  front of  H2  is 2



3 0
3 years ago
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