False, although the air is moving in an equilibrium us normal humans can not see the air actually moving. So it is false.
Answer:
Explanation:
1. Miles travelled in an average month

2. Using a gasoline powered vehicle
(a) Moles of heptane used
(b) Equation for combustion
C₇H₁₆ + O₂ ⟶ 7CO₂ + 8H₂O
(c) Moles of CO₂ formed
(d) Volume of CO₂ formed
At 20 °C and 1 atm, the molar volume of a gas is 24.0 L.
3. Using an electric vehicle
(a) Theoretical energy used

(b) Actual energy used
The power station is only 85 % efficient.

(c) Combustion of CH₄
CH₄ + 2O₂ ⟶ CO₂ +2 H₂O
(d) Equivalent volume of CO₂
The heat of combustion of methane is -802.3 kJ·mol⁻¹

4. Comparison

The reaction between the reactants would be:
CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻
Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.
CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I 0.11 0 0
C -x +x +x
E 0.11 - x x x
Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
Since the given information is Kb, let's find Ka in terms of Kb.
Ka = Kw/Kb, where Kw = 10⁻¹⁴
So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]
Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>
Answer: The coefficient for the diatomic oxygen (O2) is 3.
Explanation:
To know the coefficient for the diatomic Oxygen, we need to balance the equation.
Fe + O2 -------> Fe2O3
LHS of the equation; Fe = 1 , O2 = 1
RHS of the equation; Fe = 2 , O = 3
∴ Multiply 'Fe' on the LHS of the equation by 4 and O2 by 3
Doing that will give the balance equation which is;
4 Fe + 3 O2 --------> 2 Fe2O3
The coefficient for the diatomic oxygen (O2) as seen from the equation is 3.
Here is the formula for density:
Density (D) = Mass (M) divided by Volume (V)
So you would do D = 6.147 divided by 9.3
As an as answer you would get: 0.6609677419g/cm^3
Additional information:
The formula for volume is:
V = M divided by D
The formula for Mass is:
M = D times V
I hope this helps :)