Answer:
sodium fluoride
Explanation:
When we add sodium fluoride to a solution of a given mixture, we get barium fluoride from Ba, which would be an insoluble salt, and silver fluoride from Ag, which would be a soluble salt.
The solubility rule will be used to determine the barium salt that forms as a precipitate and leaves Ag+ salt in the solution.
From the following equations, we will see that the precipitate is formed in Ba but Ag remains dissolved in the solution.
Answer:
0.5475 grams of stomach acid, HCl, are neutralized by one tablet of Tums.
Explanation:
Mass of calcium carbonate = 750.0 mg = 0.750 g
Moles of calcium carbonate =
According to reaction , 1 mole of calcium carbonate reacts with 2 moles pf HCl.
Then 0.0075 moles of calcium carbonate will recat with:
of HCl.
Mass of 0.015 mol of HCl:
0.015 mol × 36.5 g/mol = 0.5475 g
0.5475 grams of stomach acid, HCl, are neutralized by one tablet of Tums.
Answer:
55.0 g/mol
Step-by-step explanation:
<em>Step 1</em>. Partial pressure of hydrogen
You are collecting the gas over water, so
At 25 °C,
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<em>Step 2</em>. Moles of H₂
We can use the <em>Ideal Gas Law</em>.
pV = nRT Divide both sides by RT
n = (pV)/(RT)
p = 732.2 Torr Convert to atmospheres
p = 732.2/760
p = 0.9634 atm
V = 291 mL Convert to litres
V = 0.291 L
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = 25 °C Convert to kelvins
T = (25 + 273.15 ) K = 298.15 K
n = (0.9632 × 0.291)/(0.082 06 × 298.15)
n = 0.2804/24.47
n = 0.011 46 mol
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<em>Step 3</em>. Moles of metal
The partial chemical equation is
M + H₂SO₄ ⟶ H₂ + …
The molar ratio of M:H₂ is 1 mol M:1 mol H₂.
Moles of M = 0.011 46× 1/1
Moles of M = 0.011 46 mol M
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<em>Step 4</em>. Atomic mass of M
Atomic mass = mass of M/moles of M
Atomic mass = 0.630/0.011 46
Atomic mass = 55.0 g/mol