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Nostrana [21]
3 years ago
8

How do you know that a combustion reaction is exothermic

Chemistry
1 answer:
kap26 [50]3 years ago
5 0
When you burn wood it gives off heat. that heat is what makes the combustion reaction exothermoc
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Which of the following is not observed in a homologous series? ​
Stolb23 [73]

Answer:

Change in chemical properties

Explanation:

4 0
3 years ago
Which best explains what happens to the carbon atoms in carbon dioxide during photosynthesis?A They are incorporated into molecu
Mademuasel [1]

Answer:

A They are incorporated into molecules of sugar.

Explanation:

Photosynthesis is the metabolic process whereby sugar molecules are synthesized by plants in the presence of sunlight (light energy). For this process to occur, carbon dioxide (CO2) and water (H2O) are needed as reactants from external sources. Hence, the photosynthetic equation is as follows:

6CO2 + 6H2O → C6H12O6 + 6O2

According to this question, the carbon atoms in carbon dioxide are incorporated into sugar molecule (glucose). It takes 6 carbon atoms to produce one glucose molecule (C6H12O6). This process involves series of reaction in the light-independent stage of photosynthesis to occur.

3 0
3 years ago
A sample of xenon gas occupies a volume of 6.80 L at 52.0°C and 1.05 atm. If it is desired to increase the volume of the gas sam
Pavlova-9 [17]

Answer:

207.03°C

Explanation:

The following data were obtained from the question:

V1 (initial volume) = 6.80 L

T1 (initial temperature) = 52.0°C = 52 + 273 = 325K

P1 (initial pressure) = 1.05 atm

V2 (final volume) = 7.87 L

P2 (final pressure) = 1.34 atm

T2(final temperature) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:

P1V1/T1 = P2V2/T2

1.05 x 6.8/325 = 1.34 x 7.87/T2

Cross multiply to express in linear form as shown below:

1.05 x 6.8 x T2 = 325 x 1.34 x 7.87

Divide both side by 1.05 x 6.8

T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)

T2 = 480.03K

Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:

°C = K - 273

°C = 480.03 - 273

°C = 207.03°C

Therefore, the final temperature of the gas will be 207.03°C

5 0
3 years ago
A 25.0 ml sample of 0.150 m benzoic acid is titrated with a 0.150 m naoh solution. what is the ph at the equivalence point? the
Ad libitum [116K]

Solution:

At the equivalence point, moles NaOH = moles benzoic acid  

HA + NaOH ==> NaA + H2O where HA is benzoic acid  

At the equivalence point, all the benzoic acid ==> sodium benzoate  

A^- + H2O ==> HA + OH- (again, A^- is the benzoate anion and HA is the weak acid benzoic acid)  

Kb for benzoate = 1x10^-14/4.5x10^-4 = 2.22x10^-11  

Kb = 2.22x10^-11 = [HA][OH-][A^-] = (x)(x)/0.150  

x^2 = 3.33x10^-12  

x = 1.8x10^-6 = [OH-]  

pOH = -log [OH-] = 5.74  

pH = 14 - pOH = 8.26  


5 0
3 years ago
Read 2 more answers
What is calcium + chlorine when doing ionic bonds
vlabodo [156]
CaCl2
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6 0
3 years ago
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