1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tems11 [23]
3 years ago
11

What is the volume of .04 mol of a gas at .9 kPa and 20 degrees celsius

Chemistry
1 answer:
siniylev [52]3 years ago
8 0
Pv=nrt
just make sure to convert temperature unit from Celsius to kalvin. r is constat
You might be interested in
Pls hurry
eimsori [14]

Answer:

plusses give me brainliest after this

The answer is: 1. periodic table

4 0
2 years ago
Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241
Mazyrski [523]

Answer:

-767,2kJ

Explanation:

It is possible to sum enthalpies of half-reactions to obtain the enthalpy of a global reaction using Hess's law. For the reactions:

1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁= −241.8 kJ

2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂= +361.7 kJ

3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl (g) ΔH₃= −92.3 kJ

4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄= − 607.9 kJ

5) H₂O(g) ⟶ H₂O(l) ΔH₅= − 44.0 kJ

The sum of (4) - (2) produce:

6) XCl₄(s) + O₂(g) ⟶ XO₂(s) + 2Cl₂(g) ΔH₆ = ΔH₄ - ΔH₂ = -969,6 kJ

(6) + 4×(3):

7) XCl₄(s) + 2H₂(g) + O₂(g) ⟶ XO₂(s) + 4HCl(g) ΔH₇ = ΔH₆ + 4ΔH₃= -1338,8 kJ

(7) - 2×(1):

8) XCl₄(s) + 2H₂O(g) ⟶ XO₂(s) + 4HCl(g) ΔH₈ = ΔH₇ - 2ΔH₁= -855,2kJ

(8) - 2×(5):

9) XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g) ΔH₉ = ΔH₈ - 2ΔH₅= <em>-767,2kJ</em>

I hope it helps!

6 0
3 years ago
Explains how commercial land use negatively impacts watersheds?
Juli2301 [7.4K]
Polluted water. The growing crops and climate variability change. Basically the farming
3 0
3 years ago
9. During an experiment the students prepared three mixtures A)Starch in water B) Sodium chloride solution C) Tincture of Iodine
il63 [147K]

Answer:

See explanation

Explanation:

Tyndall effect refers to the scattering of light in a solution. Tyndall effect occurs when the size of particles in the solution exceeds 1 nm in diameter. Such solutions are actually called false solutions.

In tincture of iodine, the size of particles in solution is less than 1 nm in diameter hence the solution does not exhibit Tyndall effect. Hence, tincture of iodine is a true solution.

Therefore, if the size of particles in solution exceeded 1nm in diameter, Tyndall effect is observed.

7 0
2 years ago
What volume of 0.25 M HCl would be needed to neutralize 45 mL of 0.12 M solution of Mg(OH)₂
dalvyx [7]

Answer:

0.38dm³

Explanation:

you just du-mb cuh

I'm jp ig

4 0
2 years ago
Other questions:
  • Select the correct answer.
    13·2 answers
  • If you could explain why as well for just #6 pleaseee I need help
    10·1 answer
  • How do an ionic bond and a covalent bond differ?
    11·2 answers
  • How could you separate a mixture of rocks and sand?
    9·1 answer
  • A chemistry teacher has a 560-cm length of magnesium ribbon. For a class experiment, each student requires an 8.5-cm length of t
    7·1 answer
  • The neutralization of H3PO4 with KOH is exothermic. H3PO4(aq)+3KOH(aq)⟶3H2O(l)+K3PO4(aq)+173.2 kJ If 60.0 mL of 0.200 M H3PO4 is
    7·1 answer
  • Select the true statement:
    15·1 answer
  • Help me pleaseeeeeeee​
    11·1 answer
  • Differentiate between homogenous and heterogeneous catalysis​
    13·1 answer
  • Separate the pennies you have into two groups: one group with pennies dated before 1982 and the other with pennies dated after 1
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!