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Anettt [7]
3 years ago
13

Calculate H for the process Hg2Cl2 ? 2Hg + Cl2 from the following information:

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

The enthalpy of the reaction of the reaction asked in the question is 265.2 kJ.

Explanation:

Hg + Cl_2\rightarrow HgCl_2,\Delta H_1 = -224kJ...(1)

Hg + HgCl_2\rightarrow Hg_2Cl_2,\Delta H_2 = -41.2kJ..(2)

Hg_2Cl_2\rightarrow 2Hg + Cl_2,\Delta H_3=?...(3)

(1)+(2)

\Delta H_4=-224kJ+(-41.2kJ)= -265.2 kJ

2Hg+Cl_2\rightarrow Hg_2Cl_2,\Delta H_4=-265.2 kJ...(4)

On reversing the equation (4)we get (3):

\Delta H_4=-265.2 kJ =-(\Delta H_3)

Hg_2Cl_2\rightarrow 2Hg+Cl_2,\Delta H_3=265.2 kJ

The enthalpy of the reaction of the reaction asked in the question is 265.2 kJ.

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