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Anettt [7]
3 years ago
13

Calculate H for the process Hg2Cl2 ? 2Hg + Cl2 from the following information:

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

The enthalpy of the reaction of the reaction asked in the question is 265.2 kJ.

Explanation:

Hg + Cl_2\rightarrow HgCl_2,\Delta H_1 = -224kJ...(1)

Hg + HgCl_2\rightarrow Hg_2Cl_2,\Delta H_2 = -41.2kJ..(2)

Hg_2Cl_2\rightarrow 2Hg + Cl_2,\Delta H_3=?...(3)

(1)+(2)

\Delta H_4=-224kJ+(-41.2kJ)= -265.2 kJ

2Hg+Cl_2\rightarrow Hg_2Cl_2,\Delta H_4=-265.2 kJ...(4)

On reversing the equation (4)we get (3):

\Delta H_4=-265.2 kJ =-(\Delta H_3)

Hg_2Cl_2\rightarrow 2Hg+Cl_2,\Delta H_3=265.2 kJ

The enthalpy of the reaction of the reaction asked in the question is 265.2 kJ.

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The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:

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                                       …… (1)

Here,

Q is the amount of heat transferred.

m is the mass of copper.

c is the specific heat of copper.

is the change in temperature of copper.

Rearrange equation (1) to calculate the temperature change.

                                   …… (2)

The value of Q needs to be converted into J. The conversion factor for this is,

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The value of Q is 4689 J.

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The value of c is .

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                         …… (3)

Here,

is the change in temperature.

is the final temperature.

is the initial temperature.

Rearrange equation (3) to calculate the final temperature.

                      …… (4)

The value of  is .

The value of  is  

Substitute these values in equation (4).

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