Part 1: 2×2×3×3×3=108 (c)
Part 2: 10×9×26×25×4=234000 (c)
Part 3: 10×9×8×7×6×5×4×3×2×1÷(3×2×1)=604800 (d)
Part 4: 11C4=11×10×9×8÷(4×3×2×1)=330 (a)
Part 5: ⅕=20% (c)
Part 6: 100-2.9=97.1 (d)
Usually the easiest way to solve this is by using a calculator. Of course only if your teacher allows you too.
Answer:
3/2
Step-by-step explanation:
move the 3x to the other side and divide it by 2
Answer:
C, 5/2
Step-by-step explanation:
3 I2x -1I + 4 = 16
Isolate absolute value:
3 I2x -1I + 4 - 4 = 16 - 4
3 I2x -1I= 12
(3 I2x -1I) / 3 = 12 / 3
I2x -1I= 4
Since the question is only asking for the positive, all you need to solve for is the +4. Solve for x
2x -1 = 4
2x -1 + 1 = 4 +1
2x = 5
2x / 2 = 5 / 2
x = 5/2 or C
Answer: ![\sqrt[5]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%7D)
I realize its probably not the largest readable font. If you are having trouble reading it, it is the square root of y; however, there is a tiny little 5 in the upper left corner to indicate a fifth root. So you would read it out as "the fifth root of y"
The rule I'm using is
![x^{1/n} = \sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D)
and the more general rule we could use is
![x^{m/n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D)
where m = 1. This rule helps convert from rational exponent form (aka fractional exponents) to radical form.
