Answer:
45 Mpa
Explanation:
The maximum shear stress,
is given by

Where T is the torque and d is the diameter.
Substituting 29820.586 N.m for T and 0.15m for d then we obtain

Answer:
Find the attachment for solution
Note: The resistance is measured in ohms (Ω). In the question Ω will replace V, where ever the resistance unit is required .
Answer:
a) 
b) 
Explanation:
From the properties of Super-heated Refrigerant 134a Vapor at
,
; we obtain the following properties for specific enthalpy and specific entropy.
So; specific enthalpy 
specific entropy 
Also; from the properties of saturated Refrigerant 134 a vapor (liquid - vapor). pressure table at
; we obtain the following properties:

Given that the power input to the compressor is 2 hp;
Then converting to Btu/hr ;we known that since 1 hp = 2544.4342 Btu/hr
2 hp = 2 × 2544.4342 Btu/hr
2 hp = 5088.8684 Btu/hr
The steady state energy for a compressor can be expressed by the formula:

By neglecting kinetic and potential energy effects; we have:



b) To determine the entropy generation; we employ the formula:

In a steady state condition 
Hence;


![\sigma _c = [200 \ lb/hr (0.2157 -0.2315) \ Btu/lb .^0R - \dfrac{(-3730.8684 \ Btu/hr)}{(40^0 + 459.67^0)^0R}]](https://tex.z-dn.net/?f=%5Csigma%20_c%20%3D%20%5B200%20%5C%20lb%2Fhr%20%280.2157%20-0.2315%29%20%5C%20Btu%2Flb%20.%5E0R%20%20-%20%5Cdfrac%7B%28-3730.8684%20%5C%20Btu%2Fhr%29%7D%7B%2840%5E0%20%2B%20459.67%5E0%29%5E0R%7D%5D)
![\sigma _c = [(-3.16 ) \ Btu/hr .^0R + (7.4667 ) Btu/hr ^0R}]](https://tex.z-dn.net/?f=%5Csigma%20_c%20%3D%20%5B%28-3.16%20%29%20%5C%20Btu%2Fhr%20.%5E0R%20%20%2B%20%287.4667%20%29%20Btu%2Fhr%20%5E0R%7D%5D)

Answer:
Explanation:
Simply put, a solar panel works by allowing photons, or particles of light, to knock electrons free from atoms, generating a flow of electricity. Solar panels actually comprise many, smaller units called photovoltaic cells. (Photovoltaic simply means they convert sunlight into electricity. The attached diagram give an ilustsration of the photovotaic pannel mounted on a roof top.
Solution
To Determine the electric power generated for
a) A still summer day.
E = A * r * H * PR
E = Total Amount of Energy in kilowatt
A = Total Surface Area
r = efficiency Rating
H = global radiation value
PR = Performance Ratio
kwh = watt * Time/1000
kwh = 100 * 35/1000
3.5
b)
kwh = watt * Time/1000
kwh = 30 *15/1000
4.5