Answer:
5.6 mm
Explanation:
Given that:
A cylindrical tank is required to contain a:
Gage Pressure P = 560 kPa
Allowable normal stress
= 150 MPa = 150000 Kpa.
The inner diameter of the tank = 3 m
In a closed cylinder there exist both the circumferential stress and the longitudinal stress.
Circumferential stress ![\sigma = \dfrac{pd}{2t}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cdfrac%7Bpd%7D%7B2t%7D)
Making thickness t the subject; we have
![t = \dfrac{pd}{2* \sigma}](https://tex.z-dn.net/?f=t%20%3D%20%5Cdfrac%7Bpd%7D%7B2%2A%20%5Csigma%7D)
![t = \dfrac{560000*3}{2*150000000}](https://tex.z-dn.net/?f=t%20%3D%20%5Cdfrac%7B560000%2A3%7D%7B2%2A150000000%7D)
t = 0.0056 m
t = 5.6 mm
For longitudinal stress.
![\sigma = \dfrac{pd}{4t}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cdfrac%7Bpd%7D%7B4t%7D)
![t= \dfrac{pd}{4*\sigma }](https://tex.z-dn.net/?f=t%3D%20%5Cdfrac%7Bpd%7D%7B4%2A%5Csigma%20%7D)
![t = \dfrac{560000*3}{4*150000000}](https://tex.z-dn.net/?f=t%20%3D%20%5Cdfrac%7B560000%2A3%7D%7B4%2A150000000%7D)
t = 0.0028 mm
t = 2.8 mm
From the above circumferential stress and longitudinal stress; the stress with the higher value will be considered ; which is circumferential stress and it's minimum value with the maximum thickness = 5.6 mm
Answer: Even low airborne concentrations (100 ppm) of ammonia may produce rapid eye and nose irritation.
Answer: The engineer will create a detailed sketch that labels all of the visual components.
Explanation:
It should be noted that the reverse engineering is required for the replacement and the modification of an existing product.
With regards to the question, the correct answer is option A "The engineer will create a detailed sketch that labels all of the visual components".
Answer: hello some aspects of your question is missing below is the missing information
The gas tank is made from A-36 steel and has an inner diameter of 1.50 m.
answer:
≈ 22.5 mm
Explanation:
Given data:
Inner diameter = 1.5 m
pressure = 5 MPa
factor of safety = 1.5
<u>Calculate the required minimum wall thickness</u>
maximum-shear-stress theory ( σ allow ) = σγ / FS
= 250(10)^6 / 1.5 = 166.67 (10^6) Pa
given that |σ| = σ allow
3.75 (10^6) / t = 166.67 (10^6)
∴ t ( wall thickness ) = 0.0225 m ≈ 22.5 mm