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lara [203]
3 years ago
15

. Which of the following formula is used for calculating current:

Engineering
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

I think non of the above because

Explanation:

Current is usually denoted by the symbol I. Ohm's law relates the current flowing through a conductor to the voltage V and resistance R; that is, V = IR. An alternative statement of Ohm's law is I = V/R.

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A pressure gage and a manometer are connected to a compressed air tank to measure its pressure. If the reading on the pressure g
mixer [17]

Answer:

h=1.122652m

Explanation:

Assuming density of air = 1.2kg/m³

the differential pressure is given by:

h^{i} =h(\frac{density of manometer}{density of flowing air}-1)\\h^{i} =h(\frac{1000}{1.2}-1)\\ h^{i}=832.33h...(1)\\\\but\\ h^{i} =\frac{change in pressure}{air density*g} \\\\h^{i} =\frac{11*10^3}{1.2*9.81}\\\\h^{i}= 934.42...(2)\\\\equating, \\\\934.42=832.33h\\\\h=1.122652m

7 0
4 years ago
When your complex reaction time is compromised by alcohol, an impaired person's ability to respond to emergency or unanticipated
babunello [35]

Answer:

decreased

Explanation:

when impaired you react slower then you would sober.

3 0
3 years ago
Ring rolling is a deformation process in which a thick-walled ring of smaller diameter is rolled into a thin-walled ring of larg
VMariaS [17]

Answer:

a)True

Explanation:

Rolling:

Rolling is a metal forming in which a material passes through two or more than two depends on conditions,rolls to produce the desired product.

Ring rolling:

 In ring rolling a thick ring compresses by rolls to produce the large diameter ring.Actually volume of material is constant so when diameter of ring increases then to compensate it, the thickness of ring reduces .In simple words we can say that in ring rolling a thick ring of smaller is rolled into a thin ring of larger diameter.  

6 0
3 years ago
Plz help electrical technology
oksano4ka [1.4K]

Answer:

OPTION A,Larger

HOPE IT HELPS

8 0
3 years ago
Read 2 more answers
(Gas Mileage) Drivers are concerned with the mileage their automobiles get. One driver has kept track of several trips by record
Effectus [21]

Answer:

import java.util.*;

public class Main {

   

   public static void main(String[] args) {

     

       double milesPerGallon = 0;

       int totalMiles = 0;

       int totalGallons = 0;

       double totalMPG = 0;

       

       Scanner input = new Scanner(System.in);

 

       while(true){

           System.out.print("Enter the miles driven: ");

           int miles = input.nextInt();

           if(miles <= 0)

               break;

           else{

               System.out.print("Enter the gallons used: ");

               int gallons = input.nextInt();

               totalMiles += miles;

               totalGallons += gallons;

               milesPerGallon = (double) miles/gallons;

               totalMPG = (double) totalMiles / totalGallons;

               System.out.printf("Miles per gallon for this trip is: %.1f\n", milesPerGallon);

               System.out.printf("Total miles per gallon is: %.1f\n", totalMPG);

           }

       }

   }  

}

Explanation:

Initialize the variables

Create a while loop that iterates until the specified condition is met inside the loop

Inside the loop, ask the user to enter the miles. If the miles is less than or equal to 0, stop the loop. Otherwise, for each trip do the following: Ask the user to enter the gallons. Add the miles and gallons to totalMiles and totalGallons respectively. Calculate the milesPerGallon (divide miles by gallons). Calculate the totalMPG (divide totalMiles by totalGallons). Print the miles per gallon and total miles per gallon.

6 0
3 years ago
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