. Which of the following formula is used for calculating current:
1 answer:
You might be interested in
Answer:
final volume V2 = 0.71136 m³
work done in process W = -291.24 kJ
heat transfer Q = 164 kJ
Explanation:
given data
mass = 1.5 kg
pressure p1 = 200 kPa
temperature t1 = 150°C
final pressure p2 = 600 kPa
final temperature t2 = 350°C
solution
we will use here superheated water table that is
for pressure 200 kPa and 150°C temperature
v1 = 0.95964 m³/kg
u1 = 2576.87 kJ/kg
and
for pressure 600 kPa and 350°C temperature
v2 = 0.47424 m³/kg
u2 = 2881.12 kJ/kg
so v1 is express as
V1 = v1 × m ............................1
V1 = 0.95964 × 1.5
V1 = 1.43946 m³
and
V2 = v2 × m ............................2
V2 = 0.47424 × 1.5
final volume V2 = 0.71136 m³
and
W = P(avg) × dV .............................3
P(avg) = =
= 400 × 10³
put here value
W = 400 × 10³ × (0.71136 - 1.43946 )
work done in process W = -291.24 kJ
and
heat transfer is
Q = m × (u2 - u1) + W .............................4
Q = 1.5 × (2881.12 - 2576.87) + 292.24
heat transfer Q = 164 kJ
Answer:
Explanation:
Height h = 1.03m
Volume v = 3780 gallons = 3780 * 0.0037851m^3 = 14.3073m^3
Time t = 13.5 mins = 13.5 * 60 = 810 seconds
Length of pool L = 14 inch = 14 * 2.54 = 35.56cm
width of pool b = 48 inch = 48 * 2.54 = 121.92 cm
a.) Consider the bernoulli's equation is given as:
consider the equation of bernoulli at the top of the pool
where atm pressure
At the top of the pool , substitute in V_1 in equation (2)
Hence equation (3) serves as the bernoullis equation at the top.
b.) Consider the equation of bernoulli's at the opening of the pool
where atm pressure and
Hence equation (6) serves as the bernoullis equation of water at the opening of the pool.
c.) Consider the equation (3) and (4)
Hence velocity is
d.) consider (7)
This is the norminal value of velocity
e.) consider the equation of flow rate interval of v and t
flow(t)= hence this is the flow rate
f.) Consider the equation cross sectional area in terms of V,v2 and t
hence this serves as the cross sectional area.
g.) Consider the equation of area from equation (8)