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tester [92]
1 year ago
11

7.35 and 7.36 For the beam and loading shown, (a) draw the shear and bending-moment diagrams, (b) determine the maximum absolute

values of the shear and bending moment.
Engineering
1 answer:
Crank1 year ago
4 0

Maximum absolute values of the shear = 28 KN

Maximum absolute values of bending moment = 5.7 KN.m

<h3>How to draw Shear Force and Bending Moment Diagram?</h3>

A) We can see the beam loaded in the first image attached.

For the shear diagram, let us calculate the shear from point load to point load.

From A to C, summing vertical to zero gives; ∑fy = 0: -20 - V = 0

V = -20 KN

From C to D, summing vertical to zero gives; ∑fy = 0: -20 + 48 - V = 0

V = 28 KN

From D to E, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - V = 0

V = 8 KN

From E to B, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - 20 - V = 0

V = -12 KN

For the bending moment diagram, let us calculate the bending moment from point load to point load.

At point A, the bending moment would be zero. Thus, M_A = 0 KN.m

At point C, taking moment about point C and equating to zero gives;

M_C = 0. Thus; 20(0.225) + M = 0

M = -4.5 KN.m

At point D, taking moment about point D and equating to zero gives;

M_D = 0. Thus; 20(0.525) - 48(0.3) + M = 0

M = 3.9 KN.m

At point E, taking moment about point E and equating to zero gives;

M_D = 0. Thus; 20(0.75) - 48(0.525) + 20(0.225) + M = 0

M = 5.7 KN.m

At point B, taking moment about point E and equating to zero gives;

M_E = 0. Thus; 20(1.05) - 48(0.825) + 20(0.525) + (20 * 0.3) + M = 0

M = 2.1 KN.m

2) From the attached diagrams, we can deduce that;

Maximum absolute values of the shear = 28 KN

Maximum absolute values of bending moment = 5.7 KN.m

Read more about shear force & bending moment diagram at; brainly.com/question/14834487

#SPJ1

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3 years ago
Air is compressed in a reversible, isothermal, steady- flow process from 15 psia, 100°F to 100 psia. Calculate the work of compr
mixas84 [53]

Answer:

|W|=169.28 KJ/kg

ΔS = -0.544 KJ/Kg.K

Explanation:

Given that

T= 100°F

We know that

1 °F = 255.92 K

100°F = 310 .92 K

P _1= 15 psia

P _1= 100 psia

We know that work for isothermal process  

W=mRT\ln \dfrac{P_1}{P_2}

Lets take mass is 1 kg.

So work per unit mass

W=RT\ln \dfrac{P_1}{P_2}

We know that for air R=0.287KJ/kg.K

W=RT\ln \dfrac{P_1}{P_2}

W=0.287\times 310.92\ln \dfrac{15}{100}

W= - 169.28 KJ/kg

Negative sign indicates compression

|W|=169.28 KJ/kg

We know that change in entropy at constant volume

\Delta S=-R\ln \dfrac{P_2}{P_1}

\Delta S=-0.287\ln \dfrac{100}{15}

ΔS = -0.544 KJ/Kg.K

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Increase vehicle control through lane position and speed adjustments is not necessary risk management, just common sense.
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A spherical container made of steel has 20 ft outer diameter and wal thickness of 1/2 inch. Knowing the internal pressure is 50
anastassius [24]

Answer:

maximum normal stress = 5975 psi

maximum shear stress = 2987.50 psi

Explanation:

Given data

dia = 20 ft

wall thickness = 1/2 inch

internal pressure  = 50 psi

To find out

the maximum normal stress and the maximum shearing stress

Solution

By the Mohr's circle we will find out shear stress

first we calculate inner radius

i.e. r = (diameter/2) - t

r = (20 × 12 in )/2 - ( 1/2 )

r =  120 - 0.5 = 119.5 inch

Now we find out maximum normal stress by given formula

normal stress = ( internal pressure× r ) / 2 t

normal stress = ( 50×119.5 ) / 2 × 0.5

maximum normal stress = 5975 psi

and minimum normal stress is 0, due to very small radius

and maximum shear stress will be

shear stress = ( maximum normal stress - minimum normal stress ) / 2

shear stress = ( 5975- 0 ) / 2

maximum shear stress = 2987.50 psi

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3 years ago
Write the design brief (identify the problem) of mine headgear​
grin007 [14]

The design brief that identified the problem of mine headgear is:

The structural structure above an underground mine shaft that facilitates the hoisting of machinery, persons, or supplies is known as a headframe (also called as a gallows frame, winding tower, hoist frame, pit frame, shafthead frame, headgear, headstock, or poppethead).

Mine headgear supports wheel systems that suspend winding cables that convey employees and ore up and down deep level shafts. These weird humanoid constructions have become the mining industry's defining emblem.

A miner's helmet consists of four major components:

Part 1: The hoist or winch is in a winding house. This component of the system is responsible for winding and unwinding the steel cable.

A motor and a control system are connected to the hoist.

When a steel cable unwinds from the winch, the mine cage and skips are lowered into the mine.

When the steel cable is wound up again, the mine cage and skips are elevated.

The sheave wheel is a pulley wheel that stands above the mining shaft in Part 2. The hoist rope travels over the sheave wheel and down the mine shaft.

The sheave wheel minimizes the mine cable's sliding friction.

Part 3: The head frame is the framework that holds the sheave wheel in place. When lifting the heavy mine cage, it must be robust enough to maintain the sheave wheel in place.

The head frame's left "legs" slope towards the hoist. This is due to the cable's strain dragging the entire frame in that direction. The sloping legs keep the head frame from tipping or collapsing.

Part 4: The cage and the jumps. Miners and equipment are transported up and down the mine in the cage. Skips are attached beside or beneath the cage.

Skips are used to transport ore and waste materials from mines.

<h3>What is a design brief?</h3>

A design brief, also called as a creative brief, is a program management document that identifies the scope, scale, and key aspects of your impending design project.

Learn more about design brief:

brainly.com/question/21422013

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