Question

A liquid refrigerant (sg=1,2) is flowing at a weight flow rate of 20,9 N/h. Refrigerant flashes into a vapor and its specific weight become 11,5 N/m^3. If the weigt flow rate remains at 20,9 N/h, compute the volume flow rate[10^-4 m^3/sec]. Express results in 10^-4 m^3/sec.

Answer 1

Answer:

Explanation:

volume of 20.9 N

= 20.9 / 11.5 m³

= 1.8174 m³

In one hour 1.8174 m³ flows

in one second volume flowing = 1.8174 / 60 x 60

= 5 x 10⁻⁴ m³

Rate of volume flow = 5 x 10⁻⁴ m³ / s .