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topjm [15]
2 years ago
11

After absorption, long-chain fatty acids and monoglycerides inside intestinal cells are

Biology
1 answer:
Romashka-Z-Leto [24]2 years ago
8 0

After absorption, long-chain fatty acids and monoglycerides inside intestinal cells are reformed into triglycerides.

<h3>Where are long chain triglycerides absorbed?</h3>

As previously mentioned, MCTs do not delay gastric emptying and are absorbed faster in the intestine than MCTs, being transported via blood to the liver.

In this case, long-chain triglycerides are oils or fats of vegetable or animal origin, and are obtained from the reaction between a fatty acid and glycerol.

See more about triglycerides at brainly.com/question/13840067

#SPJ11

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What happens if you put a metal object in contact with a conductor?
OLEGan [10]

Answer:

It will heat up the metal

Explanation:

Metal itself is a conductor so it will also heat up

hope this helped

8 0
3 years ago
Can you please help please
Neko [114]

The answer to that answer is B


6 0
4 years ago
Read 2 more answers
A segment of DNA is 400 base pairs long and contains 2 restriction sites for the restriction enzyme HindIII. This DNA is cut wit
r-ruslan [8.4K]

Answer:

I would expect to see 3 bands after completing DNA gel electriphoresis and staining the gel.

Explanation:

The restriction enzyme Hind3 has two Recognization sites in the 400 base pair long DNA molecule.

     As a result the restriction enzyme Hind3 with generate 2 cuts in the target 400 base pair long DNA molecule.

     The number of 2 cuts in the target DNA molecule will generate 3 DNA fragments.From this point of view it can be stated that 3 bands will form after completing DNA electrophoresis and staining the gel.

5 0
4 years ago
In trout, Gene A affects body color and yellow color (allele a) is recessive to red. In a particular river system you find that
hjlf

Answer:

The frequency of the dominant A allele is 0,4 or 40%.

Explanation:

In this population, we have:

- "A" red body color Dominant

- "a" yellow doy color Recessive

So, individuals AA and Aa will be red and trouts aa will be yellow.  In this case, 64% of the fish are red, so they are AA or Aa.

If the population is in Hardy-Weinberg equilibrium the following will be true:

p^{2}+2pq+q^{2}=1

Where:

p^{2}=frequency of AA

2pq= frequency of Aa

q^{2}=frequency of aa

It is known that 64% of population is red, in other words:

p^{2}+2pq=0,64

Or AA+Aa=0,64

So, it is possible to find the value of q^{2} (aa):

p^{2}+2pq+q^{2}=1

(0,64)+q^{2}=1

q^{2}=1-0,64q^{2}=0,36

Now, there are two alleles in this population, therefore their frequencies will be:

p+q=1

So, from q^{2} it is possible to find q and p:

q=\sqrt{q^{2} }

q=\sqrt{0,36}

q=0,6

And:

p+q=1\\p=1-q\\p=1-0,6\\p=0,4

7 0
3 years ago
Cellular Respiration<br> begins with?
lorasvet [3.4K]
The answer is Glycolysis
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3 years ago
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