Ask question

Ask question

All categories

2 years ago

13

The store has p packages of batteries. Each package contains 12 batteries. Write an expression that shows the number of batterie

s.

1 answer:

photoshop1234 [79]2 years ago

6 0

Hey:)

an expression that shows the number of batteries is '12p'

hope this helps.

You might be interested in

N - 8, when n = -8<br> please do this asap

Shtirlitz [24]

Answer:

-8-8 is equal to -16

6 0

3 years ago

Bezzdna [24]

We know that
Applying the law of cosines

c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]

in this problem

a=7.6 in

b=8.6 in

c=7.4 in

C=angle V

cos C=[7.6²+8.6²-7.4²]/[2*7.6*8.6]----> 0.5887

C=arc cos (0.5887)--------> C=53.93°-------> C=53.9°

the answer is

angle V is 53.9°

5 0

3 years ago

Can someone please help me with these? I'm giving 100 points so please.

Cerrena [4.2K]

Answer:

1. $-2\frac{9}{12}$

2. $10\frac{1}{8}$

3. 3

4. -1 > x

Step-by-step explanation:

1.

$-\frac{33}{12} \\12 * 2 = 24\\33 - 24 = 9\\-2\frac{9}{12}$

2.

$10 \frac{1}{8} / \frac{3}{4} = 13\frac{1}{2} \\13\frac{1}{2} + \frac{1}{2} = 14$

3. All share the factor of 3

4. Open circle is used for < (less than) or > (greater than). Shade to the right for > or ≥.

I hope this helps! May I please have brainliest? :)

8 0

3 years ago

Read 2 more answers

a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh

sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

$h=-16t^2+32t+48$

Let us assume that we need to find the time by it to reach the ground. It means h = 0

$-16t^2+32t+48=0$

The above is a quadratic equation. The value of t is given by :

$t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s$

So, it will take 2.11 seconds to reach the ground.

6 0

3 years ago

What operation do you use to find the power of bases<br><br><br><br> please answer quick

Rufina [12.5K]

I believe its exponent

6 0

3 years ago