32g of oxygen is required to burn 4g of hydrogen.
Define molecular mass.
A specific molecule's mass is expressed in daltons and is known as the molecular mass (m) (Da or u). Due to the varying isotopes of an element that they contain, multiple molecules of the same substance can have distinct molecular weights.
The total atomic mass of every atom in a molecule, calculated using a scale with hydrogen, carbon, nitrogen, and oxygen having atomic masses of 1, 12, 14, and 16, respectively. For instance, water has a molecular mass of 18 (2 + 16), which consists of two hydrogen atoms and one oxygen atom. known also as molecular weight.
In ,2H2+O2-----> 2H2O
H 2 molecules have a mass of 2 g/mol.
The molecular weight of oxygen is 32 g/mol.
When the chemical equation is balanced,
To totally react, 32 g of oxygen are needed for every 22=4 g of hydrogen.
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Answer:
you can use FILTRATION
STEP :-
1) put a hot water into breaker .
2) stir the solution until the sand dissolve
3) filtrate the solution
4) take the filtrate and evaporate under the sun
then you can get the water and salt too
Hope this helps :)
The amount of heat deposited on the skin is 2.26 kJ.
<h3>What is the amount of heat given off by 1.0 g of steam?</h3>
The amount of heat given off by steam is determined using the formula below:
Quantity of heat = mass * latent heat of vaporization.
Moles of steam = 1.0/18
Heat = 1.0/18 * 40.7
Heat deposited = 2.26 kJ
In conclusion, the quantity of heat is determined from the latent heat of vaporization and the moles of steam.
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Answer:
6
Explanation:
p orbital can hold up to six electron. Argon electron configuration will be 1s²2s²2p⁶3s²3p⁶
Answer:
Zn =⇒ Zn+2(0.10) + 2e- (anode)
Zn+2(?M) + 2e- === Zn(s) (cathode)
Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn
E = E^o -0.0592 log Q; in this case E^o is zero.
E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2
23 mV x 1 volt/1000mv = 0.023 Volts
0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
0.023 = -0.0296 { log 0.10 – log [Zn+2] }
0.023 = -0.0296{ -1 - log[Zn+2] }
0.023 = +0.0296 + 0.0296log[Zn+2]
-0.0066 = 0.0296log[Zn+2]
-0.22= log[Zn+2]
[Zn+2] = 10^-0.22 = 0.603 Molar
