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sesenic [268]
2 years ago
9

Someone PLEASEEEEE HELP!! :(

Mathematics
1 answer:
Ratling [72]2 years ago
3 0

The equation that represents the line that passes through the points is y-1 = \frac{5}{4}(x-1). The correct option is D. y-1 = \frac{5}{4}(x-1)

<h3>Equation of a line </h3>

From the question, we are to determine the equation of the line that passes through the given points

Using the formula

\frac{y-y_{1} }{x-x_{1}} =\frac{y_{2}-y_{1} }{x_{2}-x_{1}}

From the give information,

x_{1} = 1 \\y_{1} = 1\\{x_{2} =5

y_{2} = 6\\

Putting the parameters into the formula,

\frac{y-1 }{x-1} =\frac{6-1}{5-1}

\frac{y-1 }{x-1} =\frac{5}{4}

∴ y-1 = \frac{5}{4}(x-1)

Hence, the equation that represents the line that passes through the points is y-1 = \frac{5}{4}(x-1). The correct option is D. y-1 = \frac{5}{4}(x-1)

Learn more on Equation of a line here: brainly.com/question/12079926

#SPJ1

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Step-by-step explanation:

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Vertices

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The formula of modulus is:

d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\

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s=\frac{perimeter}{2}\\s=\frac{32.44}{2}\\ s=16.22\\Area=\sqrt{s(s-a)(s-b)(s-c)}\\=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}\\=\sqrt{(16.22)(0.99)(6.22)(9.01)}\\=\sqrt{899.91}\\=29.99\ square\ units

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