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Ilya [14]
2 years ago
6

Can someone answer this as soon as possible.

Mathematics
1 answer:
Afina-wow [57]2 years ago
8 0
The second one because it seems like the one that makes sense the most
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What is the equation for a slope -1 through the point (2,0)?
RUDIKE [14]

Answer:

y = - x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 1, thus

y = - x + c ← is the partial equation

To find c substitute (2, 0) into the partial equation

0 = - 2 + c ⇒ c = 0 + 2 = 2

y = - x + 2 ← equation of line

4 0
3 years ago
How do I solve this equation... if a=5 b=7 and c=12 What is: a(b + c) x 2?
julia-pushkina [17]

Answer:

190 is the answer of the equation.

Step-by-step explanation:

a(b + c) × 2

Now putting the values of a,b and c.

5(7+12)×2

= 5(19)×2

= 95×2

= 190

5 0
3 years ago
Will mark Brainliest. Question above
docker41 [41]
Area = (10 * 14) + (1/2 * 6 * 10) = 170m^2
3 0
3 years ago
The hawaiian alphabet has 12 letters. How many permutations are possible for five of these letters
guajiro [1.7K]

Answer: The answer is 50980

Step by Step Explanation:

First, temporarily assume that two letters with I are different, call them i 1 and i 2. Three "a" are also called as a 1, a 2 and a 3, and two h as h 1 and h 2. Then there are 11 * 10 * 9 * 8 * 7 = 55440 possible "words" (one of 11 is the first letter, 10 is the second, and so on). But because equal letters do the same "words," some "words" were counted twice or more. We have to deduct the number of "parasitic" counts although it is fairly small. The words that counted more than once are divided into many disjoint sets: 1) with two I but without repetitions of a and h; 2) with two h but without repetitions of a and I 3) with two a but without repetitions of I and h; 4) with three a but without repetitions of I and h; 5) with two I and two a's; 6) two i's and tree a's; 7) two i's and two h's 8) two h's and two a's; 9) two h's and one tree. The first category includes terms counted twice and its scale is (5 * 4) * (6 * 5 * 4) = 2400 (the first I stays at one of the 5 positions, the second at one of the 4, then 11-2i-1h-2a=6). So we have 2400/2 = 1200 to subtract. Group 2 gives -600 as well, and group 3 also. Group 4 gives * (6 * 5) = 1800 (5 * 4 * 3), and the terms are counted 6 times, -300. Groups 5, 7 , 8: 5 * 4 * 3 * 2 * 6 = 720 and counted four times, therefore -180. Group 6 and 9: 5 * 4 * 3 * 2 * 1 = 120, with 12 counts, -10. Altogether -(1200 * 3 + 300 + 180 * 3 + 10 * 2) = -4460.The answer will be 55440-4460 = 50980.

3 0
4 years ago
3 to the 3rd power - 4 + 5 to the 2nd power​
AnnZ [28]

Answer:

48

Step-by-step explanation:

(3^3)-4+(5^2)

27-4+25

23+25

48

6 0
3 years ago
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