Answer:
( About ) 0.03232 M
Explanation:
Based on the units for this reaction it should be a second order reaction, and hence you would apply the integrated rate law equation "1 / [X] = kt + 1 / [
]"
This formula would be true for the following information -
{ = the initial concentration of X, k = rate constant, [ X ] = the concentration after a certain time ( which is what you need to determine ), and t = time in minutes }
________
Therefore, all we have left to do is plug in the known values. The initial concentration of X is 0.467 at a time of 0 minutes, as you can tell from the given data. This is not relevant to the time needed in the formula, as we need to calculate the concentration of X after 18 minutes ( time = 18 minutes ). And of course k, the rate constant = 1.6
1 / [X] = ( 1.6 )( 18 minutes ) + 1 / ( 0.467 ) - Now let's solve for X
1 / [X] = 28.8 + 1 / ( 0.467 ),
1 / [X] = 28.8 + 2.1413...,
1 / [X] = 31,
[X] = 1 / 31 = ( About ) 0.03232 M
Now for this last bit here you probably are wondering why 1 / 31 is not 0.03232, rather 0.032258... Well, I did approximate one of the numbers along the way ( 2.1413... ) and took the precise value into account on my own and solved a bit more accurately. So that is your solution! The concentration of X after 18 minutes is about 0.03232 M
The question is incomplete, so I tried to find a similar problem online. It is shown in the attached picture. The reaction is
PCl₃ + Cl₂ ⇆ PCl₅
Then, we use the ICE (Initial-Change-Excess) approach as follows:
PCl₃ + Cl₂ ⇆ PCl₅
I 0.5 0.5 0.3
C -x -x +x
E 0.5-x 0.5-x 0.3+x
Total pressure: 0.5 - x + 0.5 - x + 0.3 + x = 1.3
Kp = [PCl₅]/[PCl₃][Cl₂]
0.18 = (0.3+x)/(0.5-x)²
Solving for x,
x= 0.21
Partial pressures would be:
<em>PCl₃ = 0.5 - 0.21 = 0.29 atm</em><em>Cl₂ = 0.5 - 0.21 = 0.29 atm</em><em>PCl₅ = 0.3+0.21 = 0.51 atm</em>
<span>Safety glasses are to be worn whenever working with acids, bases, or any flammable materials. Let the instructor know immediately about any glassware breakage or chemical spills that may occur so that proper cleanup procedures can be instituted.Use pipet fillers whenever pipeting any fluid.Whenever working with acids or bases, have the chemicals available at your work station, do not carry pipets with fluid across the room.When diluting acids, pour the acid into the water, NOT water into acid as this may cause spattering of the acid.When acid is mixed with another reagent, an exothermic reaction may occur which heats up the container, This is natural, so do not panic and spill contents.All volatile materials must be handled in a hood with the exhaust fan on.When refluxing any solutions, perform this operation under a hood, and use boiling beads in the reflux vessel to prevent any excessive "bumping" and possible glass breakage.Use heat-resistant gloves and/or tongs when handling hot glassware, chinaware, etc.Use plastic gloves when handling any hazardous materials to prevent skin contact.Label and date all chemical mixtures that are made up and kept for future use.Do not store basic solutions in glass containers with glass stoppers, use plastic or rubber stoppers.Dispose of all used solutions in an approved manner as directed by the instructor.Empty all used inoculated bacteriological media from test tubes or dishes into a designated container so that it may be sterilized before disposal.Before leaving, turn off all power and heat to the apparatus you have used, or place in the standby mode.Clean all spatulas, glassware, and dishes after use and before storage to prevent contamination.<span>Return all chemicals you are using to their proper storage space.Be familiar with the use of the eye-wash, the laboratory shower (if equipped), and the first-aid kit if they are needed at any time.</span></span>
Distilled water.high school Lab
Answer:
See explanation.
Explanation:
1. There are 8 electrons. Elements that end with 2p orbitals are in the 2nd period (aka row) of the periodic table. Elements that have 4 electrons in 2p are in the 16th group (aka column) (column 16 may also be referred to as 6A) of the periodic table. So looking at row 2, column 16, we can see that the first diagram is of O, Oxygen.
2. 8 electrons. This is the same diagram as the one above.
3. 13 electrons. Elements ending with 3p are in period 3. Elements with 1 valence electron in a p orbital are in group 13 (aka group 3A).
4. 7 electrons. We already know 2p is period 2. 3 valence electrons in a p orbital means that it is in group 15/group 5A.
I did not write the answers for #3 and 4 but they can be easily found on a periodic table with the info I gave.
