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3 years ago

Need someone to answer this please

Chemistry

1 answer:

deff fn [24]3 years ago

8 0

A. Hadley cell goes to trade winds.
B.Ferral cells goes to Westerlies
C.polar cell polar goes to post easterlies

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What is the mass of oxygen in 300 grams of carbonic acid (H2CO3)

DENIUS [597]

mass of carbonic acid = 300g

molar mass of H2CO3 = 2H + C + 3 O

= 2 x 1.008+ 12.01 + 3 x 16

= 62.03g/mol

moles of H2CO3 = mass/Molar mass

= 300/62.03

= 4.8364 moles

1 mole H2CO3 has 3 moles Oxygen

4.8364 moles H2CO3 contains

= 3 x 4.8364 moles Oxygen = 14.509 moles Oxygen

moles = mass/Molar mass

mass of oxygen = moles x Molar mass of Oxygen

= 14.509 x 16

= 232.15g Oxygen

mass of oxygen in 300g of carbonic acid(H2CO3) = 232.15g

7 0

4 years ago

Based on the following chemical equation how many hydrogen atoms are present in the products side?

OleMash [197]

The number of Hydrogen atoms = 6 atoms

<h3>Further explanation</h3>

Given

Reaction

N₂ + 3H₂ ⇒ 2NH₃

Required

The number of Hydrogen atoms

Solution

The reaction coefficient of a chemical equation shows the mole ratio of the reacting compound.

On a compound the reaction coefficient indicates the number of molecules

Whereas the subscript after the atom shows the number of atoms in that compound

Product from the reaction : 2NH₃

Number of H-atoms :

= 2 x 3

= 6 atoms

7 0

3 years ago

Find the equilibrium value of [CO] if Kc=14.5 : CO (g) + 2H2 (g) ↔ CH3OH (g) Equilibrium concentrations: [H2] = 0.322 M and [CH3

Annette [7]

Answer:

The equilibrium value of [CO] is 1.04 M

Explanation:

Chemical equilibrium is the state to which a spontaneously evolving chemical system, in which a reversible chemical reaction takes place. When this situation is reached, it is observed that the concentrations of substances, both reagents and reaction products, they remain constant over time. That is, the rate of reaction of reagents to products is the same as that of products to reagents.

Reagent concentrations and products in equilibrium are related by the equilibrium constant Kc. Being:

aA + bB ⇔ cC + dD

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }$

Then this constant Kces equals the multiplication of the concentrations of the products raised to their stoichiometric coefficients between the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

In this case:

$Kc=\frac{[CH_{3}OH ]}{[CO]*[H_{2} ]^{2} }$