Answer:
Points perpendicularly toward the line of charge and decreases in strength at larger distances from the line charge
Explanation:
The electric field for a uniform line of charge is given by E = λ/2πε₀r where λ = charge density and r = distance from line of charge.
If λ is negative, E is negative so it points in the negative direction towards the line of charge.
Also, since for negative charges, electric field lines end up in them, the electric field for an infinitely long negative line of charge points towards the charge perpendicular to it.
Also as r increases, E decreases since E ∝ 1/r
So, the electric field decreases at larger distances from the line of charge.
So,<u> the electric field of a negative infinite line of charge Points perpendicularly toward the line of charge and decreases in strength at larger distances from the line charge.</u>
Answer:
40 m/s North
Explanation:
m = 10 kg
u = 4 m/s North = 4 j
m1 = 5 kg
v1 = 8 m/s west = - 8 i
m2 = 4 kg
v2 = 10 m/s east = 10 i
m3 = m - m1 - m2 = 10 - 5 - 4 = 1 kg
Let the velocity of third fragment is v3 = v
Using the conservation of momentum
m x u = m1 x v1 + m2 x v2 + m3 x v3
10 x 4 j = 5 x (- 8i) + 4 x 10 i + 1 x v3
40 j = - 40 i + 40 i + v3
v3 = 40 j
Thus, the third fragment moves in the direction of north with velocity 40 m/s
Answer:
Answer 11
Explanation:
. Newton's law of gravitation, statement that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them
Answer:
a)
b)
Explanation:
From the question we are told that:
Weight
Decrease in kinetic energy
Increase in potential energy
Velocity
Elevation
a)
Generally the equation for Change in Kinetic Energy is mathematically given by
b)
Generally the equation for Change in Potential Energy is mathematically given by
Answer:
100J
Explanation:
Kinetic energy=1/2mv^2
Kinetic energy=(1/2 x 8)x5^2
Kinetic energy=4x25
Kinetic energy=100
100J