When Stone B collides with Stone A during Test 2, Stone B stops and Stone A begins to move. Which statement BEST describes the m
omentum in Test 2?
A
Stone A moves away from Stone B at a velocity of 4 m/s, and the momentum is conserved.
B
Stone A moves away from Stone B at a velocity of 2 m/s, and the momentum is not conserved.
C
Stone A moves away from Stone B at a velocity of 4 m/s, and the momentum is not conserved.
D
Stone A moves away from Stone B at a velocity of 2 m/s, and the momentum is conserved.
A
Stone A moves away from Stone B at a velocity of 4 m/s, and the momentum is conserved.
B
Stone A moves away from Stone B at a velocity of 2 m/s, and the momentum is not conserved.
C
Stone A moves away from Stone B at a velocity of 4 m/s, and the momentum is not conserved.
D
Stone A moves away from Stone B at a velocity of 2 m/s, and the momentum is conserved.
1 answer:
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Answer:
The steps are outlined in the explanation below.
Explanation:
The average velocity is derived midpoint from the initial to the final velocity. Here is the proof:
Find the total displacement:
let the displacement be given by the letter s
Then since the average velocity is defined as:
where t = final time
t₀ = initial time
v = final speed
v₀ = initial time
where x denotes the position, then
where v = and dx = change in distance with respect to time.
The answer is no. If you are dealing with a conservative force and the object begins and ends at the same potential then the work is zero, regardless of the distance travelled. This can be shown using the work-energy theorem which states that the work done by a force is equal to the change in kinetic energy of the object.
W=KEf−KEi
An example of this would be a mass moving on a frictionless curved track under the force of gravity.
The work done by the force of gravity in moving the objects in both case A and B is the same (=0, since the object begins and ends with zero velocity) but the object travels a much greater distance in case B, even though the force is constant in both cases.
W=KEf−KEi
An example of this would be a mass moving on a frictionless curved track under the force of gravity.
The work done by the force of gravity in moving the objects in both case A and B is the same (=0, since the object begins and ends with zero velocity) but the object travels a much greater distance in case B, even though the force is constant in both cases.