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olga55 [171]
4 years ago
12

A probe is launched from earth and lands on mars the gravitational acceleration on mars is 3.7 m/s. Which statement best compare

s the mass and weight of the probe
Physics
2 answers:
Ugo [173]4 years ago
8 0
There are no correct statements among the choices you gave us.

When the probe arrives on the surface of Mars, its mass is the same
as it was on Earth, and at every place along the way.

But its weight is   (3.7/9.8) = 37.8% of what it weighed on Earth.
Natali [406]4 years ago
5 0
The answer is B)<span>The mass of the probe remains the same, but the weight of the probe decreases</span>
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Suppose two children push horizontally, but in exactly opposite directions, on a wagon containing a third child. The first child
koban [17]

Answer:

0.1 m/s^2, in the direction of F2

Explanation:

The magnitude of F2 is larger than that of F1: this means that the wagon will tend to move in the direction of F2. Therefore, the direction of friction will be opposite to the direction of motion, therefore in the direction of F1.

Let's now take the direction of the force exerted by the second child, F2, as positive direction. Then the direction of F1 and of the force of friction (F_f) will be negative: so we have

F_2 = +90.0 N\\F_1 = -75.0 N\\F_f = -12.0 N

We can write the equation of the forces for the third child+wagon:

F_1+F_2+F_f = ma

where

m = 30.0 kg is the combined mass of the child + the wagon

Now we can solve the equation for a, to find the acceleration:

a=\frac{F_2+F_1+F_f}{m}=\frac{90-75-12}{30}=0.1 m/s^2

4 0
3 years ago
An ideal parallel-plate capacitor having circular plates of diameter D that are a distance d apart stores energy U when it is co
Stella [2.4K]

Answer:\sqrt{3}D

Explanation:

Given

Diameter of Plates is D

distance between Plates is d

Energy Stored in the Plates is U

Suppose fixed Potential is V

Energy is given by

U=\frac{1}{2}CV^2

where C=capacitance

C=\frac{\epsilon A}{d}

where A=area of Plates

A=\frac{\pi D^2}{4}

Thus C=\frac{\epsilon \cdot \pi \cdot D^2}{4d}

Keeping all other factors as same

U\propto D^2----1

For triple the Energy

3U\propto (D')^2-----2

divide 1 and 2 we get

\frac{U}{3U}=\frac{D^2}{D'^2}

D'=\sqrt{3}D

Thus the diameter should be change to \sqrt{3} times of original value          

3 0
3 years ago
You look in the sky and see two jetliners that you know are of equal size, yet one appears to be much larger. Because of your kn
Ksju [112]

Answer:

Because of the knowledge of <u>relative size</u>, it will be assumed that the smaller jetliner is farther away.

Explanation:

According to the theory of relative size, the distance that an object has to the viewing individual affects the perception of the individual regarding the size of the object.

As stated in this case, one of the jetliners is farther away from the other. Therefore, even if the jets are of equal size, the one that is at a greater distance is perceived to be smaller as it is at a greater viewing range. The one that is nearer to the individual seems bigger in comparison to the one farther away due to a closer viewing range.

Therefore, the jet that is nearer appears larger.

To know more about relative size, refer to:

brainly.com/question/19998265

#SPJ4

8 0
2 years ago
As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length
grin007 [14]

Answer:

As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is Lw. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g.

Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward).

Question:

If the bottom of your window is a height hb above the ground, what is the velocity vground of the pot as it hits the ground? You may introduce the new variable vb, the speed at the bottom of the window, defined by

vb=Lwt+gt2.

Express your answer in terms of some or all of the variables hb, Lw, t, vb, and g.

The correct answer is

vground = (t²+lw²+(2t³+2t²)×g×Lw+(t⁴+2t³+t²) ) ∧ 0.5 = vb² +2g×vbt+1/2gt²

Explanation:

We have from the relation

v = u + gt, S = ut + 1/2 gt², v² = u² + 2gS

in this case S = hb, u = vb=Lwt+gt2.  and v = vground

therefore v² = (Lwt+gt²)² + 2 × g × hb

= (Lwt+gt²)² + 2 × g ×  (Lwt+gt²)×t + 1/2 gt² = vb² +2g×vbt+1/2gt²

vground = (t²+lw²+(2t³+2t²)×g×Lw+(t⁴+2t³+t²) ) ∧ 0.5

7 0
3 years ago
The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by variou
Kipish [7]

Answer:

The excess charge on earth's surface was calculated to be 4.56 × 10⁵ C

Explanation:

Using the formula for an electric field;

E = kQ/r²

k = 1/(4πε₀) = 8.99 × 10⁹ Nm²/C²

E = 100N/C

r = radius of the earth = 6400 km = 6400000m

Q = Er²/k = 100 × (6400000)²/(8.99 × 10⁹)

Q = 455617.4 C = 4.56 × 10⁵ C

Hope this helps!!!

6 0
3 years ago
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