The change in speed of this object is 3m/s
According to Newton's second law;
F = ma
F = mv/t
Given the following parameters
Force F = 8.0N
mass m = 16kg
time t = 4.0s
Required
speed v
Substitute the given parameters into the formula
v = Ft/m
v = 8 * 6/16
v = 48/16
v = 3m/s
Hence the change in speed of this object is 3m/s
Learn more here: brainly.com/question/19072061
Answer:
Explanation:
The velocity of a wave in a string is equal to:
v = √(T / (m/L))
where T is the tension and m/L is the mass per length.
To find the mass per length, we need to find the cross-sectional area of the thread.
A = πr² = π/4 d²
A = π (3.0×10⁻⁶ m)²
A = 2.83×10⁻¹¹ m²
So the mass per length is:
m/L = ρA
m/L = (1300 kg/m³) (2.83×10⁻¹¹ m²)
m/L = 3.68×10⁻⁸ kg/m
So the wave velocity is:
v = √(T / (m/L))
v = √(7.0×10⁻³ N / (3.68×10⁻⁸ kg/m))
v ≈ 440 m/s
The speed of sound in air at sea level is around 340 m/s. So the spider will feel the vibration in the thread before it hears the sound.
Answer:
9080 N
Explanation:
Consider the two motions of the ball.
In the downward motion, initial velocity, <em>u</em>, is 0 (because it falls from rest) and the distance is 28.7 m. Using the equation of motion and using <em>g</em> as 9.8 m/s²,
<em>v² = u² + 2as</em>
<em>v² = </em>0² + 2 × 9.8 × 28.7<em> </em>= 562.52
<em>v = </em>19.7 m/s
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For the downward motion, the initial velocity is unknown, the final velocity is 0 and initial velocity is desired. <em>g</em> is negative because the motion is upwars.
<em>0² = v² - </em>2 × 9.8 × 19.8
<em>v² = </em>388.08
<em>v = </em>10.7 m/s
The change in momentum = 0.502(10.7 -(23.7)) = 21.7868 kgm/s
The impulse = change in monetum
Ft = 21.7868 kgm/s
But t = 2.4 ms
![[tex]F = \dfrac{21.7868}{2.4\times10{-3}} = 9078 \text{ N}](https://tex.z-dn.net/?f=%5Btex%5DF%20%3D%20%5Cdfrac%7B21.7868%7D%7B2.4%5Ctimes10%7B-3%7D%7D%20%3D%209078%20%5Ctext%7B%20N%7D)
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<span>First, a problem would be the sheer amount of wind resistance. If an object travels as far as even just one hundred miles it could encounter different wind patterns that could change the trajectory of the object. Second would be the size of the projectile. This creates a problem because the bigger it is, the more momentum it could potentially pick up, given that it is not too big to complete the distance. This is another problem with size, how far the projectile can actually travel. You would have to actually calculate the ideal size of said object to make sure it could actually make the distance you're looking for. hope it helps:)</span>
Answer:250.03m
Explanation:
Initial velocity =u=51mph
Angle=β=37
Acceleration due to gravity=g=10
The distance covered by the football is the range
Range=(u^2xsin2β)/g
Range=(51^2xsin(2x37))/10
Range=(51x51xsin74)/10
Range=(2601xsin74)/10
Range=(2601x0.9613)/10
Range=(2500.3)/10
Range=250.03m
