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Maksim231197 [3]

1 year ago

5

Draw a ray diagram for a diverging lens that has a focal length of -10 cm when an object is placed 30 cm from the lens's surface

. Calculate the position of the image and list the characteristics of the image.

1 answer:

Bond [772]1 year ago

4 0

Explanation:

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A balloon filled with helium gas has an average density of Q,-0.41 kg/m'. The density of the air is Qa-1.23 kg/m3. The volume of

Citrus2011 [14]

Answer:

a) $(Qa*g*Vb)-(Qh*Vb*g)=(Qh*Vb*a)\\where \\g=gravity [m/s^2]\\a=acceleration [m/s^2]$

b) a = 19.61[m/s^2]

Explanation:

The total mass of the balloon is:

$massball=densityheli*volumeheli\\\\massball=0.41 [kg/m^3]*0.048[m^3]\\massball=0.01968[kg]\\\\$

The buoyancy force acting on the balloon is:

$Fb=densityair*gravity*volumeball\\Fb=1.23[kg/m^3]*9.81[m/s^2]*0.048[m^3]\\Fb=0.579[N]$

Now we need to make a free body diagram where we can see the forces that are acting over the balloon and determinate the acceleration.

In the attached image we can see the free body diagram and the equation deducted by Newton's second law

6 0

2 years ago

Ne4ueva [31]

The answer would be Conduction

4 0

2 years ago

Which statement is true? A) The work done to lift an object 6 meters is greater than the gravitational potential energy it gains

inna [77]

The work required to raise an object to a height is equal to the gravitational potential energy the object gains. <em>(C)</em>

4 0

3 years ago

What mass of electrons would be required to just neutralize the charge of 4.8 g of protons?

suter [353]

Let's calculate the total charge of M=4.8 g=0.0048 kg of protons.
Each proton has a charge of $q=1.6 \cdot 10^{-19} C$ , and a mass of $m_p = 1.67 \cdot 10^{-27}kg$ . So, the number of protons is
$N_p = \frac{M}{m_p}= \frac{0.0048 kg}{1.67 \cdot 10^{-27}kg}=2.87 \cdot 10^{24}$ And so the total charge of these protons is $Q_p = qN_p = (1.6 \cdot 10^{-19}C)(2.87 \cdot 10^{24})=4.6\cdot 10^5 C$

So, the neutralize this charge, we must have $N_e$ electrons such that their total charge is
$Q_e = -4.6 \cdot 10^5 C$
Since the charge of each electron is $q_e = -1.6 \cdot 10^{-19}C$ , the number of electrons needed is
$N_e = \frac{Q_e}{q}= \frac{-4.6 \cdot 10^5 C}{-1.6 \cdot 10^{-19}C}=2.87 \cdot 10^{24}$
which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is $m_e=9.1 \cdot 10^{-31}kg$ , the total mass of electrons should be
$M_e = N_e m_e = (2.87 \cdot 10^{24})(9.1 \cdot 10^{-31}kg)=2.6 \cdot 10^{-6}kg$

6 0

2 years ago

A gas bottle contains 0.650 mol of gas at 730 mm Hg pressure. If the final pressure is 1.15 atm, how many moles of gas were adde

AlekseyPX

Answer:

0.779 mol

Explanation:

Since the gas is in a bottle, the volume of the gas is constant. Assuming the temperature remains constant as well, then the gas pressure is proportional to the number of moles:

$p \propto n$

so we can write

$\frac{p_1}{n_1}=\frac{p_2}{n_2}$

where

p1 = 730 mm Hg = 0.96 atm is the initial pressure

n1 = 0.650 mol is the initial number of moles

p2 = 1.15 atm is the final pressure

n2 is the final number of moles

Solving for n2,

$n_2 = n_1 \frac{p_2}{p_1}=(0.650 mol)\frac{1.15 atm}{0.96 atm}=0.779 mol$

6 0

3 years ago

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