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Ne4ueva [31]
3 years ago
7

I need help plz!!! Please help...

Physics
1 answer:
RSB [31]3 years ago
4 0

Answer: 60

Explanation:

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If the pressure of a substance is increased during a boiling process, will the temperature also increase, or will it remain cons
7nadin3 [17]

Answer:

on increasing pressure, temperature will also increase.

Explanation:

Considering the ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Thus, at constant volume and number of moles, Pressure of the gas is directly proportional to the temperature of  the gas.

P ∝ T

Also,  

Also, using Gay-Lussac's law,

\frac {P_1}{T_1}=\frac {P_2}{T_2}

Thus, on increasing pressure, temperature will also increase.

4 0
3 years ago
One beaker contains 100 mL of pure water and second beaker contains 100 mL of seawater. The two beakers are left side by side on
Harman [31]

Answer: The beaker containing pure water has decreased more.

Explanation:

In both cases, the decrease of water level is due to evaporation. We know that evaporation is a surface phenomenon. In the case of salt water, the salt molecules somewhat hinders the evaporation process of the water molecules and hence the salt water evaporates at a slower rate than pure water.

Hence, pure water level falls more.

7 0
3 years ago
Read 2 more answers
A 55.6-kg skateboarder starts out with a speed of 2.44 m/s. He does 80.4 J of work on himself by pushing with his feet against t
Vikentia [17]

(a) -1620.8 J

The initial kinetic energy of the  skateboarder is:

K_i = \frac{1}{2}mu^2 = \frac{1}{2}(55.6 kg)(2.44 m/s)^2=165.5 J

where m is the skateboarder's mass and u his initial speed;

While the final kinetic energy is

K_f = \frac{1}{2}mv^2 = \frac{1}{2}(55.6 kg)(7.24 m/s)^2=1457.2 J

where v is his final speed.

So the change in kinetic energy is

\Delta K=K_f - K_i = 1457.2 J -165.6 J = 1291.6 J

According to the work-energy theorem, the change in mechanical energy (kinetic+potential) of the skateboarder is equal to the work done on it:

\Delta K + \Delta E_p = W + W_f

where

W = 80.4 J is the work done by the skateboarder on himself

W_f = -244 J is the work done by friction

\Delta E_p = E_p_f - E_p_i is the change in gravitational potential energy

Solving for \Delta E_p,

\Delta E_p = W+W_f - \Delta K=80.4 J - 244 J - 1457.2 J = -1620.8 J

(b) 2.97 m

The change in potential energy of the skateboarder can be written as

\Delta E_p = mg \Delta h

where

m = 55.6 kg is the mass

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h is the change in vertical height of the skateboarder

Solving for \Delta h,

\Delta h = \frac{\Delta E_p}{mg}=\frac{-1620.8 J}{(55.6 kg)(9.8 m/s^2)}=-2.97 m

Where the negative sign means the skateboarder has moved downwards. Since we are interested only in the absolute value, the answer is

h = 2.97 m

7 0
3 years ago
Two physics students are arguing about superconductors and their discovery, Jeffe says that he can use a
Liono4ka [1.6K]

Answer:

B on edge2020-2021

Explanation:

5 0
3 years ago
A charge is placed on a spherical conductor of radius r1. This sphere is then connected to a distant sphere of radius r2 (not eq
irina [24]

Answer:

Option 3 = both spheres are at the same potential.

Explanation:

So, let us complete or fill the missing gap in the question above;

" A charge is placed on a spherical conductor of radius r1. This sphere is then connected to a distant sphere of radius r2 (not equal to r1) by a conducting wire. After the charges on the spheres are in equilibrium BOTH SPHERES ARE AT THE SAME POTENTIAL"

The reason both spheres are at the same potential after the charges on the spheres are in equilibrium is given below:

=> So, if we take a look at the Question again, the kind of connection described in the question above (that is a charged sphere, say X is connected another charged sphere, say Y by a conducting wire) will eventually cause the movement of charges(which initially are not of the same potential) from X to Y and from Y to X and this will continue until both spheres are at the same potential.

5 0
3 years ago
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