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Alika [10]
2 years ago
7

1. Find the volume of the pyramid. 5 in 11 in 9 in 74

Mathematics
1 answer:
Oduvanchick [21]2 years ago
5 0

The volume of the pyramid with the given length, width and height is 165in³.

<h3>What is the volume of the pyramid?</h3>

The volume of a right rectangular pyramid is expressed as;

V = ( L × W × H ) / 3

Given that;

  • Length L = 11in
  • Width W = 9in
  • Height H = 5in

We substitute into the equation above.

V = ( L × W × H ) / 3

V = ( 11in × 9in × 5in ) / 3

V = 495in³ / 3

V = 165in³

The volume of the pyramid with the given length, width and height is 165in³.

Learn more about volume of pyramid here: brainly.com/question/17615619

#SPJ1

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In which:

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Item a:

We start with 75 grams, and then work with a half-life of 3.8 days, hence the amount after t daus is given by:

N(t) = 75(0.5)^{\frac{t}{3.8}}

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This is N when t = 3.8, hence:

N(t) = 75(0.5)^{\frac{3.8}{3.8}} = 37.5

37.5 grams of the gas remains after 3.8 days.

Item c:

This is t for which N(t) = 10, hence:

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10 = 75(0.5)^{\frac{t}{3.8}}

(0.5)^{\frac{t}{3.8}} = \frac{10}{75}

\log{(0.5)^{\frac{t}{3.8}}} = \log{\frac{10}{75}}

\frac{t}{3.8}\log{0.5} = \log{\frac{10}{75}}

t = 3.8\frac{\log{\frac{10}{75}}}{\log{0.5}}

t \approx 11

The amount remaining will be of 10 grams after approximately 11 days.

More can be learned about exponential functions at brainly.com/question/25537936

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