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Ede4ka [16]
4 years ago
9

Why is a force required to keep a body moving with a uniform speed in a circular motion?

Physics
1 answer:
andrew-mc [135]4 years ago
6 0
Because if there's no force on the object, then it just moves in a straight line.
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if pes represents the potential energy stored in a spring in kg•m^2/s^2 and x represents the change in the springs length from i
musickatia [10]
Unit for x - the change in the spring length:
x = [ m ]
PE s =  1/2 k x²
[ kg m² / s² ] = 1/2 k * [ m² ]   /: m²
k = [ kg / s² ]
Answer: The unit for spring constant k is kg/ s²
8 0
3 years ago
A bowling ball has a mass of 5 kg. What happens to its momentum when the speed increases from 1 m/s to 2 m/s?
Alona [7]
<span>The initial momentum is 5 kg m/s and the final momentum is 10 kg m/s

'cause P = m*v, when we increase either m or v, P also increases by the same expression, 

P = 5 * 2 = 10

So, option D is your answer!!

Hope this helps!

</span>
5 0
3 years ago
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As you drive in your car at 22.5 mi/h, you see a child’s ball roll into the street ahead of you. You hit the brakes and stop as
evablogger [386]

Answer:

Explanation:

Speed of car =22.5miles/hr

U=22.5miles/hour

Applied brake and come to rest

Final velocity, =0

t, =2sec

Given that,

Speed=distance /time

Then,

Distance, =speed, ×time

Converting mile/hour to m/s

Given that

Use: 1 mile= 1600 m, 1 h= 3600s

22.5miles/hour × 1600m/mile × 1hour/3600s

Therefore, 22.5mile/hour=10m/s

Using speed =10m/s

Distance =speed ×time

Distance=10×2

Distance, =20m

The distance travelled before coming to rest is 20m.

5 0
3 years ago
Two balls have the same mass. One ball moving along the positive x axis and the other ball moving along the positive y axis unde
Paladinen [302]
In a completely inelastic collision, the two objects stick together after the collision.
7 0
3 years ago
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You are explaining to your friends why astronauts feel weightless while orbiting in the space shuttle. They ask you to prove thi
meriva

Answer:

Explanation:

Force of gravity = GMm/r^2 = ma

a being the acceleration due to gravity at some distance r from the center of the Earth.  I'll use 6400 km for the radius of the Earth so r = 6734 km or 6734000 meters

a = GM/r^2

plugging in G = 6.67 x 10^-11

M is the mass of the Earth = 6 x 10^24

and r is from above

a = 8.825 m/s^2  = 0.9g

so 90% the acceleration of gravity on the surface.

5 0
3 years ago
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