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3 years ago

The centripetal force acting on the space shuttle

Physics

2 answers:

tamaranim1 [39]3 years ago

7 0

Answer:

(4) weight

Explanation:

The centripetal force acting on the space shuttle in orbit is given by:

$F=m\frac{v^2}{r}$

where

m is the mass of the shuttle

v is the tangential speed of the shuttle

r is the radius of its circular orbit

When the shuttle orbits the Earth, the centripetal force that keeps the shuttle in circular motion is given by the gravitational attraction between the shuttle and the Earth, which corresponds to the weight of the shuttle, and it is given by:

$F=G\frac{Mm}{r^2}$

where

G is the gravitational constant

M is the Earth's mass

And this force, therefore, corresponds to the centripetal force.

mario62 [17]3 years ago

7 0

Option (4) is correct. The centripetal force acting on the space shuttle is equal to the weight of the space shuttle.

Explanation:

The centripetal force is the force that is experienced by a body when it is moving in a circular path. As the body moves, the force experienced by the body towards its center and it is called as the centripetal force.

When the space shuttle present in the space is moving around the Earth in a particular orbit, there is a force acting on the space shuttle due to its speed in the circular path. This force is the centripetal force.

To keep the space shuttle to move in its definite path, the weight of the space shuttle acts in the direction opposite to the centripetal force and keeps the shuttle from moving out of the path.

Thus, Option (4) is correct. The centripetal force acting on the space shuttle is equal to the weight of the space shuttle.

Learn More:

1. What is the acceleration of the block under friction brainly.com/question/7031524

2. The net force acting on the refrigerator brainly.com/question/4033012

3. The result of the unbalanced force acting on a body is brainly.com/question/2720955

Answer Details:

Grade: High School

Subject: Physics

Chapter: Circular motion

Keywords:

Centripetal, force, space, shuttle, earth, inertia, weight, momentum, weight, circular, definite path.

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A 0.40 kg mass hangs on a spring with a spring constant of 12 N/m. The system oscillated with a constant amplitude of 12 cm. Wha

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Answer:

The maximum acceleration of the system is 359.970 centimeters per square second.

Explanation:

The motion of the mass-spring system is represented by the following formula:

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Where:

$x(t)$ - Position of the mass with respect to the equilibrium position, measured in centimeters.

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The acceleration experimented by the mass is obtained by deriving the position equation twice:

$a (t) = -\omega^{2}\cdot A \cdot \cos (\omega\cdot t + \phi)$

Where the maximum acceleration of the system is represented by $\omega^{2}\cdot A$ .

The natural frequency of the mass-spring system is:

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Where:

$k$ - Spring constant, measured in newtons per meter.

$m$ - Mass, measured in kilograms.

If $k = 12\,\frac{N}{m}$ and $m = 0.40\,kg$ , the natural frequency is:

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3 years ago

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Answer:

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Explanation:

Given that,

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Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

$F.d=\dfrac{1}{2}m(v^2-u^2)$

Finally, it stops, v = 0

$F.d=-\dfrac{1}{2}m(u^2)$

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2 years ago

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Know what ? There might be too much information given in this question. I want to check, because it's possible that it might not even all fit together.

To calculate my answer, I only used the voltage and the current. I didn't use the "60 watts", and I'm curious to know whether it even fits with the given voltage and current.

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Well gadzooks and sure enough ! The three numbers given in the question all go together nicely.

And not only THAT !

The answer could have been calculated by using ANY TWO of them.

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