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3 years ago

8

If the mass of an object is 5 kg, the gravitational field strength is 2 and the change in height is 5 m, what is the change in g

ravitational potential energy stored?

1 answer:

Aloiza [94]3 years ago

7 0

Answer:

50joules

Explanation:

See the explanation from the image I have provided above.

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You buy a magnifying glass at the store. The lens in the magnifying glass is a double convex lens, a lens with two convex curved

Leokris [45]

Answer:

30 cm

Explanation:

f = Focal length = 25 cm

R = Radius of curvature (both sides are equal)

$\mu$ = Refractive index of lens = 1.6

The lens maker formula is given by

$\frac{1}{f}=(\mu-1)(\frac{1}{R_1}-\frac{1}{R_2})\\\Rightarrow \frac{1}{f}=(\mu-1)(\frac{1}{R}-\frac{1}{-R})$ minus sign because it is on the other side

$\\\Rightarrow \frac{1}{f}=(\mu-1)\frac{2}{R}\\\Rightarrow R=2(\mu-1)f\\\Rightarrow R=2(1.6-1)\times 25\\\Rightarrow R=30\ cm$

The radius of curvature of the glass surface is 30 cm

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3 years ago

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Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.

Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and $g=9.8m/s^2$ the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

$\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}$

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

$\displaystyle d={\frac {20^{2}\sin(2\cdot 30^\circ )}{9.8}}$

$\displaystyle d={\frac {400\sin(60^\circ )}{9.8}}$

$d=35.35\ m$

The range is 35.35 m

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3 years ago