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masha68 [24]
2 years ago
9

35.67 g of NaNO3 is dissolved in water to make a 0.500 M solution. What is the volume of the solution in liters?

Chemistry
1 answer:
Alex17521 [72]2 years ago
8 0
Sorry but I have no idea
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A 35.40 gram hydrate of sodium carbonate, Na2CO3•nH2O, is heated to a constant mass. Its final weight is 30.2 g. What is formula
Sever21 [200]

Answer:

Na₂CO₃•H₂O

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After it is heated, the remaining mass is the mass of sodium carbonate.

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Convert masses to moles:

30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃

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Normalize by dividing by the smallest:

0.285 / 0.285 = 1.00 mol Na₂CO₃

0.289 / 0.285 = 1.01 mol H₂O

The ratio is approximately 1:1.  So the formula of the hydrate is Na₂CO₃•H₂O.

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What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)?
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