<em><u>A</u></em><em><u>. </u></em><em><u>R</u></em><em><u>E</u></em><em><u>D</u></em><em><u> </u></em><em><u>W</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em><em><u>S</u></em><em><u> </u></em><em><u>I</u></em><em><u>S</u></em><em><u> </u></em><em><u>N</u></em><em><u>O</u></em><em><u>T</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>L</u></em><em><u>I</u></em><em><u>G</u></em><em><u>H</u></em><em><u>T</u></em><em><u> </u></em><em><u>W</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em><em><u> </u></em><em><u>B</u></em><em><u>E</u></em><em><u>C</u></em><em><u>A</u></em><em><u>U</u></em><em><u>S</u></em><em><u>E</u></em><em><u> </u></em><em><u>THE</u></em>RE<em><u> </u></em><em><u>I</u></em><em><u>S</u></em><em><u> </u></em><em><u>N</u></em><em><u>O</u></em><em><u>T</u></em><em><u> </u></em><em><u>RED</u></em><em><u> </u></em><em><u>W</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em><em><u>.</u></em>
<em><u>A</u></em><em><u>L</u></em><em><u>S</u></em><em><u>O</u></em><em><u> </u></em><em><u>I</u></em><em><u>F</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u> </u></em><em><u>D</u></em><em><u>O</u></em><em><u>N</u></em><em><u>T</u></em><em><u> </u></em><em><u>B</u></em><em><u>E</u></em><em><u>L</u></em><em><u>I</u></em><em><u>E</u></em><em><u>V</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>E</u></em><em><u>A</u></em><em><u>R</u></em><em><u>C</u></em><em><u>H</u></em><em><u> </u></em><em><u>I</u></em><em><u>T</u></em><em><u> </u></em><em><u>F</u></em><em><u>R</u></em><em><u>O</u></em><em><u>M</u></em><em><u> </u></em><em><u>G</u></em><em><u>O</u></em><em><u>O</u></em><em><u>G</u></em><em><u>L</u></em><em><u>E</u></em>
The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.
<h3>What is velocity?</h3>
Velocity can be defined as the ratio of the displacement and time of a body.
To calculate the final velocity of Skater 1 we use the formula below.
Formula:
- mu+MU = mv+MV............ Equation 1
Where:
- m = mass of the first skater
- M = mass of the second skater
- u = initial velocity of the first skater
- U = initial velocity of the second skater
- v = final velocity of the first skater
- V = final velocity of the second skater.
make v the subject of the equation.
- v = (mu+MU-MV)/m................ Equation 2
Note: Let left direction represent negative and right direction represent positive.
From the question,
Given:
- m = 105 kg
- u = -2 m/s
- M = 71 kg
- U = 5 m/s
- V = -3.4 m/s.
Substitute these values into equation 2
- v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
- v = (-210+355+241.4)/105
- v = 386.4/105
- v = 3.68 m/s
- v ≈ 3.7 m/s
Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.
Learn more about velocity here: brainly.com/question/25749514
True
The electromagnet will become stronger if we add more coils because there are more field lines in a loop then there is in a straight piece of wire. In a solenoid there are a lot of loops and they are concentrated in the middle, as more loops are added the field lines get larger, therefore making the electromagnet stronger.
The equation of the car is given by the equation,
x(t) = 2.31 + 4.90t² - 0.10t⁶
If we are going to differentiate the equation in terms of x, we get the value for velocity.
dx/dt = 9.8t - 0.6t⁵
Calculate for the value of t when dx/dt = 0.
dx/dt = 0 = (9.8 - 0.6t⁴)(t)
The values of t from the equation is approximately equal to 0 and 2.
If we substitute these values to the equation for displacement,
(0) , x = 2.31 + 4.90(0²) - 0.1(0⁶) = 2.31
(2) , x = 2.31 + 4.90(2²) - 0.1(2⁶) = 15.51
Thus, the positions at the instants where velocity is zero are 2.31 and 15.51 meters.