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ololo11 [35]
3 years ago
7

A monkey pushes a rock horizontally on a frictionless table with a net force of 10 N for 2.0 m. How much kinetic energy does the

rock gain?
Round the answer to two significant digits
Physics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

The answer is 20J

Explanation:

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A 78.5-kg man is standing on a frictionless ice surface when he throws a 2.40-kg book horizontally at a speed of 11.3 m/s. With
kirill [66]

Answer:

The man moves across the ice with a speed of 0.345m/s.

Explanation:

From the conservation of linear momentum, we have that the total linear momentum before the book throw is equal to the total linear momentum just after it. Since the initial velocity of the system is zero (so the initial momentum is zero), we have that:

m_mv_m+m_bv_b=0\\\\v_m=-\frac{m_b}{m_m} v_b

Where m_m is the mass of the man, m_b is the mass of the book, and v_m and v_b are their velocities. Plugging in the given values, we can compute the speed of the man (ignoring the negative sign, because we care about the magnitude, not the direction):

v_m=\frac{2.40kg}{78.5kg}(11.3m/s)=0.345m/s

In words, the resulting speed of the man is 0.345m/s.

8 0
3 years ago
Read 2 more answers
A magnetic field is applied to a freely floating uniform iron sphere with radius R = 2.00 mm. The sphere initially had no net ma
grigory [225]

Answer:

\omega=4.2704*10^-^5 rad/s

Explanation:

Angular Momentum Formula For atoms=L_{atom}=0.12Nm_{s}h

Where:

m_{s}h is the momentum for one atom (m_s is the spin quantum number)

N is the number of atoms=\frac{N_{A}*m}{M}

Where:

N_A is Avogadro Number

m is the mass of sphere

M is the molar mass of iron

Angular Momentum Formula For atoms will be=L_{atom}=0.12\frac{N_{A}m}{M} m_{s}h

Angular Momentum of Sphere=L_{sphere}=I\omega

where:

I=\frac{2mR^{2}}{5}

So,Angular Momentum of Sphere=L_{sphere}=\frac{2mR^{2}}{5}\omega

Angular Momentum of sphere=Angular Momentum of atoms

L_{sphere}=L_{atom}

\frac{2mR^{2}}{5}\omega=0.12\frac{N_{A}m}{M} m_{s}h

For iron, m_s =\frac{1}{2}. So above equation will become:

\omega=\frac{0.12*5*N_{A}h}{4*M*R^{2} }

Where R=2mm, M=0.0558Kg/mol (Molar Mass of iron),h=Planck's Constant/2π

\omega=\frac{0.12*5*(6.022*10^{23})(6.63*10^{-34}/2*\pi)}{4*0.0558*(2*10^{-3})^{2}}

\omega=4.2704*10^-^5 rad/s

5 0
3 years ago
What trends were seen in Mendeleev’s periodic table?
katrin [286]
He arranged his periodic table by each elements atomic mass
3 0
3 years ago
Read 2 more answers
With what speed must a ball be thrown directly upward so that it remains in the air for 10 seconds?
MA_775_DIABLO [31]

Answer:

◆ See the attachment photo.

◆ Don't forget to thanks

◆ Mark as brainlist.

7 0
3 years ago
Plz someone help me Asap​
-Dominant- [34]

Answer:

all I know is C

are there more questions? anyone?

-KARL IS STOOPID

Explanation:

6 0
3 years ago
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