This question is incomplete, the complete question is;
In a survey, 55% of the voters support a particular referendum. If 40 voters are chosen at random,
find the mean and variance for the number of voters who support the referendum.
Answer:
a) The Mean is 22
b) Variance is 9.9
Step-by-step explanation:
Given that;
55% of the voters support a particular referendum p = 0.55
q = 1 - p = 1 - 0.55 = 0.45
sample size n = 40
a)
Mean = sample size n × p
Mean = 40 × 0.55
Mean = 22
Therefore the Mean is 22
b)
Variance = n × p × q
so we substitute
Variance = 40 × 0.55 × 0.45
Variance = 9.9
Therefore the Variance is 9.9
Answer:
6 different possible outfits
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
For SIMPLE interest :
1210 + 1210 * .09 * 7 = <u> $ 1972.30</u>
For ANNUAL COMPOUNDING of interest
1210 ( 1 + .09)^7 = <u>$ 2211.93</u>
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I do not know which one you need....what are you studying presently?
Answer:
Step-by-step explanation:
In 15 minutes, Jennifer has mowed of the lawn (given in problem). This means that it will take her to mow the entire lawn, assuming a constant rate.
Equation:
Let represent the entire lawn: