A hot metal ball is hung in an oven that is maintained at 700 K; and it cools. When the temperature of the ball is 950 K, it is

Question

2 years ago

13

losing heat at a rate of 0.15 J/min. At what rate will the ball lose heat when the ball reaches 820 K

2 answers:

r-ruslan [8.4K] · Answer 1 · 2023-10-26T16:12:15+03:00

Answer:

At 820 K, the object lose heat at the rate of 0.072 J/min.

Explanation:

By using Newton's cooling law, the formula to calculate the rate of cooling R is,

R=-k(T-To)

where k is a constant, T is the temperature of the object and To is the temperature of the surrounding.

At T=950 K, R=0.15 J/min and To=700 K,

Therefore, 0.15=-k(950-700)

k=0.15/250 J/K min.

At T=820 K,

R=-(0.15 / 250)*(820-700)

R=-0.072 J/min

Therefore the rate of heat loss at T=820 K is 0.072 J/min.

Know more about Newton's cooling law.

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rjkz [21] · Answer 2 · 2023-10-26T14:41:30+03:00

Answer:

The ball will lose heat at the rate of 0.072 J/min.

Explanation:

According to the Newton's cooling law, the rate of cooling R is given by the formula.

R=-k(T-To)

where k is a constant, T is the temperature of the object and To is the temperature of the surrounding.

Initially, R=0.15 J/min, To=700 K and T=950 K.

So 0.15=-k(950-700)

k=-0.15/250 J/K min.

Finally, To=700 K and T=820 K

R=-(-0.15/250)(820-700)

R= 0.072 J/min

Know more about Newton's cooling law.

#SPJ10